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Re: How many four digit numbers that are divisible by 4 can be formed usin [#permalink]
total possible combinations
unit digit as 0 = 6*5*3*1 ; 90
unit digit as 2/6 ; and (1,3,5,7) in tens 5*5*4*2 = 200
unit digit as 4 and (2,6) in tens ; 5*5*2*1 = 50
unit digit as 4 and 0 in tens ; 6*5*1*1 = 30
total = 90+200+50+80 ; 370
IMO C



Bunuel wrote:
How many four digit numbers that are divisible by 4 can be formed using the digits 0 to 7 if no digit is to occur more than once in each number?

A. 520
B. 432
C. 370
D. 353
E. 345


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Re: How many four digit numbers that are divisible by 4 can be formed usin [#permalink]
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Hi all,

I reasoned as following, please let me know if it makes sense:

total possible combinations of 4-digit numbers out of non-repeating values from 0->7: 7*7*6*5=1470 (i.e., not counting zero as a first digit)

Now, 1470 takes into account odd and even values. I'm interested in values divisible by 4, so I will split in halves 1470 twice, i.e.: once to get only even values, and again to get only values divisible by 4.

This leads to something close to 370, so my approach seems to work!

Thanks all
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Re: How many four digit numbers that are divisible by 4 can be formed usin [#permalink]
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Re: How many four digit numbers that are divisible by 4 can be formed usin [#permalink]
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