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# How many integers 100>n>10 are such that, if the

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Manager
Joined: 05 Sep 2007
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How many integers 100>n>10 are such that, if the [#permalink]

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21 Oct 2007, 14:22
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many integers 100>n>10 are such that, if the digits of n are reversed, the resulting integer is n+9?
Director
Joined: 11 Jun 2007
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21 Oct 2007, 14:41
el1981 wrote:
How many integers 100>n>10 are such that, if the digits of n are reversed, the resulting integer is n+9?

i am probably wrong but i'll take a shot at it:

i get 8 but only by logical thinking (no formulas)

12, 23, 34, 45, 56, 67, 78, 89

in order for it to be n+9, the units and tens digit has be be consecutive (since n + 10 would just be a change in the tens digit 10x)
VP
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21 Oct 2007, 14:53
This is a 2 digit #

any two digit # is of the form 10*x+y

Now its given 10*y + x = 10*x+y + 9 (this is n+9)

So y=x+1

Hence there are 8 numbers

12
23
34
45
56
67
78
89
Manager
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21 Oct 2007, 19:32
Vikram - great formula.
21 Oct 2007, 19:32
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# How many integers 100>n>10 are such that, if the

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