eddwwaarrd wrote:
I don't get this. Can someone explain more? Somebody please. Thanks
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GMAT Club Forum mobile appHi
eddwwaarrdI have merely elaborated on solutions given by
chetan2u and
gracieBetween 1 and 1000(both inclusive),
there are 1 digit numbers, 2 digit numbers, and 3 digit numbers.
There are no 1 digit number that has repeated digits
[9 possibilities]For two digit numbers, 0 can't be the first digit
The first digit can be 1-9
[9 possibilities]The second digit can be 0,1-9(except the first digit)
[9 possibilities]Total possible 2 digit numbers are 9*9 = 81
For three digit numbers, again 0 can't be the first digit
The first digit can be 1-9
[9 possibilities]The second digit can be 0,1-9(except the first digit)
[9 possibilities]The third digit can be any of the 8 digits that are not the first and second digits
[8 possibilities]Total possible 3 digit numbers are 9*9*8 = 81*8 = 648
Total numbers(without repeated digits) between 0 and 1000 are
\(9+81+648 = 738\)Therefore, the numbers which have repeated digits are 1000 - 738 =
262(Option C)
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