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# How many of the 42 people in a group are employed students?

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Director
Joined: 01 May 2007
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How many of the 42 people in a group are employed students? [#permalink]

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23 Sep 2007, 11:33
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How many of the 42 people in a group are employed students?

1) 29 of the 42 people are employed.
2) 24 of the 42 people are students.

OA to follow.

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Manager
Joined: 29 Jul 2007
Posts: 182

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23 Sep 2007, 14:23
well, i would pick C if i were to assume that there are only two groups that consist of 42 people. But, however, this is not explicitly stated. So E?

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Director
Joined: 01 May 2007
Posts: 795

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23 Sep 2007, 17:01
It is E, so I'm guessing that is the reason. Seems like a screwy question if you ask me.[/quote]

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GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5034

Kudos [?]: 438 [0], given: 0

Location: Singapore

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23 Sep 2007, 20:22
St1:
Only tells us 29 are employed. How many of the employed are students, we have no clue. Insufficient.

St2:
Only tells us 24 of the group are students. How many of these 24 are employed, we have no idea. Insufficient.

Using st1 and st2 doesn't provide further clues. Insufficient.

Ans E

(Note: If you tried to solve this using a table, you would find that there isn't sufficient information)

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CEO
Joined: 21 Jan 2007
Posts: 2734

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Location: New York City

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07 Jan 2008, 12:23
draw out a double set matrix. u have all the "total" info on the sides but nothing on the inside of the table. u need at least one element on the inside, along with the totals, to solve the question.
_________________

You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

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Intern
Joined: 07 Jan 2008
Posts: 21

Kudos [?]: 4 [0], given: 0

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07 Jan 2008, 14:41
11..

Let X be the employed students..

n( E only ) + n( S only ) + X = 42
[ 29 – X ] + [ 24 – X ] + X = 42

X = 11

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VP
Joined: 09 Jul 2007
Posts: 1098

Kudos [?]: 141 [0], given: 0

Location: London

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07 Jan 2008, 15:34
dvdv wrote:
11..

Let X be the employed students..

n( E only ) + n( S only ) + X = 42
[ 29 – X ] + [ 24 – X ] + X = 42

X = 11

OA has already been posted as E, but just out of curiosity how do you get 11 just with the formulae. i tried the diagram but could not come to any clue?

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SVP
Joined: 04 May 2006
Posts: 1881

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Schools: CBS, Kellogg

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07 Jan 2008, 19:50
dvdv wrote:
11..

Let X be the employed students..

n( E only ) + n( S only ) + X = 42
[ 29 – X ] + [ 24 – X ] + X = 42

X = 11

I find some gaps in your fomula
first: I think the correct is "-" not "+", if "+" X can not be 11
second: from the information of the problems, you can not assume that the group of none-student and none-employed is zero.

That is why answer should be E
_________________

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Intern
Joined: 07 Jan 2008
Posts: 21

Kudos [?]: 4 [0], given: 0

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08 Jan 2008, 21:18
what is this option E ?? I am new to this group and just wondering.. I cant see options mentioned in the problem. And what is OA ??

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Re: DS: Venn Diagram?   [#permalink] 08 Jan 2008, 21:18
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