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How many real solutions has |2x - 3|/5 - |x + 1|/5 = x - 2?

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Manager
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Joined: 21 Feb 2019
Posts: 125
Location: Italy
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How many real solutions has |2x - 3|/5 - |x + 1|/5 = x - 2?  [#permalink]

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New post 30 Mar 2019, 09:55
2
12
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A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

38% (02:26) correct 63% (02:32) wrong based on 128 sessions

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How many real solutions has the following equation got?

\(\frac{|2x - 3|}{5} - \frac{|x + 1|}{5} = x - 2\)

A. None
B. 1
C. 2
D. 3
E. Infinite
Manager
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Joined: 21 Feb 2019
Posts: 125
Location: Italy
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Re: How many real solutions has |2x - 3|/5 - |x + 1|/5 = x - 2?  [#permalink]

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New post 01 Apr 2019, 12:13
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Solution attached.
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Joined: 09 Apr 2018
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Re: How many real solutions has |2x - 3|/5 - |x + 1|/5 = x - 2?  [#permalink]

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New post 16 Apr 2019, 02:34
1
lucajava wrote:
How many real solutions has the following equation got?

\(\frac{|2x - 3|}{5} - \frac{|x + 1|}{5} = x - 2\)

A. None
B. 1
C. 2
D. 3
E. Infinite


Using critical key point method, Only one solution is obtained. i.e. X=3/2
Intern
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Joined: 14 Jan 2019
Posts: 12
Re: How many real solutions has |2x - 3|/5 - |x + 1|/5 = x - 2?  [#permalink]

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New post 25 May 2019, 07:28
Official answer please
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Re: How many real solutions has |2x - 3|/5 - |x + 1|/5 = x - 2?   [#permalink] 25 May 2019, 07:28
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