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# How many seconds will it take for a car that is traveling at a constan

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Math Expert
Joined: 02 Sep 2009
Posts: 58060
How many seconds will it take for a car that is traveling at a constan  [#permalink]

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29 Jan 2019, 05:06
00:00

Difficulty:

45% (medium)

Question Stats:

69% (02:16) correct 31% (02:51) wrong based on 71 sessions

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How many seconds will it take for a car that is traveling at a constant rate of 45 miles per hour to travel a distance of 220 yards? (1 mile=1,760 yards)

A. 8
B. 9
C. 10
D. 11
E. 12

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Re: How many seconds will it take for a car that is traveling at a constan  [#permalink]

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29 Jan 2019, 05:14
Bunuel wrote:
How many seconds will it take for a car that is traveling at a constant rate of 45 miles per hour to travel a distance of 220 yards? (1 mile=1,760 yards)

A. 8
B. 9
C. 10
D. 11
E. 12

1 mile = 1760 yards
220 yards = 220/1760 = 0.125 miles

.125 = 45* t
t = .125/45 hrs
t= .125 * 3600/45
t = 10 sec
IMO C
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Re: How many seconds will it take for a car that is traveling at a constan  [#permalink]

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29 Jan 2019, 05:25
Bunuel wrote:
How many seconds will it take for a car that is traveling at a constant rate of 45 miles per hour to travel a distance of 220 yards? (1 mile=1,760 yards)

A. 8
B. 9
C. 10
D. 11
E. 12

rate = 45 miles / hr

rate in sec = 45 /3600 miles/sec

Distance in miles 220 yards,

1 mile = 1760 yards
1 yard = 1/1760
220 yards = 220 /1760 yards

t = Distance / speed
= $$\frac{220}{1760} * \frac{3600}{45}$$

= 10

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How many seconds will it take for a car that is traveling at a constan  [#permalink]

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06 Mar 2019, 08:00
Bunuel wrote:
How many seconds will it take for a car that is traveling at a constant rate of 45 miles per hour to travel a distance of 220 yards? (1 mile=1,760 yards)

A. 8
B. 9
C. 10
D. 11
E. 12

Rate = 45 kms/ hour

Or, $$\frac{45}{3600}$$ kms/second ----- (I)

Distance = 220 yards

Or, $$\frac{220}{1760}$$miles -------(II)

Time = $$\frac{45}{3600}*\frac{1760}{220}$$

Solving this we get ,

Time = 10 seconds
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How many seconds will it take for a car that is traveling at a constan   [#permalink] 06 Mar 2019, 08:00
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