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Re: How many three-digit integers exist such that all their digi [#permalink]
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honchos wrote:
How many three-digit integers exist such that all their digits are even?

A. 80
B. 100
C. 120
D. 125
E. 135

Bunuel,

This is Quantitative :: Problem solving :: Probability & Combinations :: M13-14

0 is also an even integer
so last digit can be filled in 5 ways- 0,2,4,6,8

for both second and third digit there are 5 possibilities-

5 X 5 X 5 = 125
_______________

This is the solution given at Gmatclubtest

The first digit can be any of the four: 2, 4, 6, or 8. For both second and third digits, there are 5 possibilities. The answer is 4∗5∗5=100.
The correct answer is B


If the first digit is 0, then the number becomes two-digit, not three-digit.
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Re: How many three-digit integers exist such that all their digi [#permalink]
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How many positive three-digit integers exist such that all their digits are even?

A. 80
B. 100
C. 120
D. 125
E. 135


The first digit has four possibilities: 2, 4, 6, or 8. The second and third digits each have 5 options: 0, 2, 4, 6, or 8. Therefore, the total number of integers is \(4 * 5 * 5 = 100\).


Answer: B
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Re: How many three-digit integers exist such that all their digi [#permalink]
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