I guess they sit around the table as you mention it in the title of the topic.

So Mary has her own chair, fixed position. Other two females around the table can sit in 2 ways: the first to the left of Mary and the second to the right or vise-versa. Now, if 3 males will sit between them then no two female or two male will sit next to each other (female-male-female-male-female-male). But these males on their spots can also sit in different ways, namely in 3! different ways, so total 2*3!=12.

Answer B.
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Lets first sit the 3 man, 2! ways.

Now since one position is fixed for women, there are 2 women left and they have 2! ways

2! X 2! = 4 answer is diff this way.

or shall we give possibility of 3 ways for women to be fixed with back facing so 3! ways, Lets discuss the doubt.

If u like my way of discussion plz give Kudos.

Since Mary's position is fixed men can be seated in 3! ways not in 2! ways. Would be easier to draw a circle and count the possible arrangements.
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Bunuel In this answer, you do not divide by number of seats around the table, as you do in other problems, for e.g. here https://gmatclub.com/forum/how-many-way ... 89695.html.

Is this because here you compute the number of total absolute positions arrangements rather than relative positions arrangement? If so, what made you do that for this question and not for the other?

Thanks,

(For those who always feel that there is some hidden gmat type of surprize) ultra tricky question in a way that special restriction (Mary's fixed place) is not even a restriction. Number of ways these people would sit around the table with Mary going round is repetitive and should be anyways taken out.
Let's fix females first -> according to formula (3-1)!=2!
It would have been 2! for males too, if not the fact that they are sitting in a big circle together with women. Thus we have 3!
3! 2! = 12

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