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How many zeros are the end of ?

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How many zeros are the end of ? [#permalink]

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New post 15 Nov 2012, 06:23
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

69% (00:51) correct 31% (00:46) wrong based on 1167 sessions

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How many zeros are at the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95

[Reveal] Spoiler:
In order to find the number of zeros we have to find out the number of 5's and 2's , because no. of 5's will be less then the number of 2's ..
[Reveal] Spoiler: OA

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New post 15 Nov 2012, 06:41
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vomhorizon wrote:
How many zeros are the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95


380! has \(\frac{380}{5}+\frac{380}{5^2}+\frac{380}{5^3}=76+15+3=94\) trailing zeros ( take only the quotient into account).

Answer: C.

For more on trailing zeros check: everything-about-factorials-on-the-gmat-85592.html

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Hope it helps.
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New post 06 Oct 2016, 11:27
Bunuel wrote:



HELLO BUNNEL, THERE WAS A FORMULA I SAW ON GMATCLUB FORUM IN WHICH TRAILING ZEROS COULD BE CALCULATED BY INCREASING THE POWERS ON INDIVIDUAL FACTORS OF A NUMBER . FOR EG 100! = 100= 2*2*5*5 = 2^2 + 5^2 NOW WE WILL INCREASE THE POWER BY ONE I.E. 2^3 +5^3 = NOW ADDING THE POWERS = 6 , PERHAPS SOMETHING ON SIMILAR LINES CAN YOU EXPLAIN TO ME THAT CONCEPT?

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Re: How many zeros are the end of ? [#permalink]

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New post 10 Sep 2017, 04:25
380/5 = 76

76/5= 15

15/5= 3

Sum of these quotients. Answer C

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Re: How many zeros are the end of ?   [#permalink] 10 Sep 2017, 04:25
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How many zeros are the end of ?

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