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# How to solve these kind of problems?

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Manager
Joined: 13 Mar 2007
Posts: 98
How to solve these kind of problems? [#permalink]

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24 Sep 2007, 15:42
Hi,
I am hard time to solve problems like the followings. Thus, if you know any general formula that can be use to solve these kinds of problems, please let me know. In other words, what is the best way to approach to these kind of the problems?

Problem #88(from OG11)
a) 16
b) 32
c) 41
d) 54
e) 68

The correct answer should be 68.

GMATPrep question:
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

The correct answer should be 25.

Question #2 is discussed here: according-to-the-directions-on-a-can-of-frozen-orange-juice-101577.html
VP
Joined: 10 Jun 2007
Posts: 1439
Re: How to solve these kind of problems? [#permalink]

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24 Sep 2007, 15:51
a) 16
b) 32
c) 41
d) 54
e) 68

R,G,W,B,Y
Five beads in pattern and ends with white. Therefore, the number of beads will be 5*integer + 3
The only number that fits is 68 = 5*13+3

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

One can of 12 ounces concentrated can produce 4*12 = 48 ounces of OJ.
You want 200 ounces with 6 serving, which is 6*200 = 1200 ounces
Therefore, you need: 1200/48 = 25 cans
CEO
Joined: 29 Mar 2007
Posts: 2559
Re: How to solve these kind of problems? [#permalink]

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24 Sep 2007, 19:30
GMAT_700 wrote:
Hi,
I am hard time to solve problems like the followings. Thus, if you know any general formula that can be use to solve these kinds of problems, please let me know. In other words, what is the best way to approach to these kind of the problems?

Problem #88(from OG11)
a) 16
b) 32
c) 41
d) 54
e) 68

The correct answer should be 68.

GMATPrep question:
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

The correct answer should be 25.

1st one. Well the pattern has to be RGWBYRGW this equals 5 +3. So we have to find a number that allows this pattern. 5(x)+3. 5*13+3=68.

2nd one:

I have seen this so many times on this forum.

Ratio is O/W=1/3 so x+3x= total

4x= total. 6*200=1200 (total ounces) x=300

Now since we want to know 12 ounce orange juice cans. Just divide 12 by 300

300/12=25. Also I think u can do it this way. x+4x=200 x=50. Since we are using 6 ounce cans we divide this by 2. again 25.

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

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24 Sep 2007, 19:56
a) 16
b) 32
c) 41
d) 54
e) 68

The sequence goes r-g-w-b-y. So after every 5 beads, a new set begins. And the third bead after a new set is the white bead. So just count of the multiples of 5 and add 3 to see if your answer is in... for instance...

16. Nearest multiple of 5 is 15, 1 bead after 15 is red. --> out
32. Nearest multiple of 5 is 30, 2 beads after 30 is green. --> out
41. Nearest multiple of 5 is 40. 1 bead after 40 is red. --> out
54. Nearest multiple of 5 is 50. 4 beads after 50 is blue. --> out
68. Nearest multiple of 5 is 65. 3 beads after 65 is white --> Ans.
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

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24 Sep 2007, 20:02
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

Each mixture has 4 cans of solutions (1 can concentrate + 3 cans water)

There are total of 1200 ounces of servings in all.
This requires 1200/12 = 100 parts of mixture. (Assume the parts are mixed with 12 ounce cans)
# of cans of concentrate needed is 100/4 = 25.
Intern
Joined: 02 Oct 2013
Posts: 6
Concentration: Finance, Strategy
Re: How to solve these kind of problems? [#permalink]

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23 Dec 2013, 09:57
bkk145 wrote:
a) 16
b) 32
c) 41
d) 54
e) 68

R,G,W,B,Y
Five beads in pattern and ends with white. Therefore, the number of beads will be 5*integer + 3
The only number that fits is 68 = 5*13+3

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

One can of 12 ounces concentrated can produce 4*12 = 48 ounces of OJ.
You want 200 ounces with 6 serving, which is 6*200 = 1200 ounces
Therefore, you need: 1200/48 = 25 cans

Is this correct or Just Lucky?: The ratio of concentrate to water is 1:3 and They need 100 12oz servings to make 200 6oz servings.

So I did: 1x + 3x = 100

4x=100
x= 25
Math Expert
Joined: 02 Sep 2009
Posts: 39722
Re: How to solve these kind of problems? [#permalink]

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24 Dec 2013, 01:53
lsantos08 wrote:
bkk145 wrote:
a) 16
b) 32
c) 41
d) 54
e) 68

R,G,W,B,Y
Five beads in pattern and ends with white. Therefore, the number of beads will be 5*integer + 3
The only number that fits is 68 = 5*13+3

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

One can of 12 ounces concentrated can produce 4*12 = 48 ounces of OJ.
You want 200 ounces with 6 serving, which is 6*200 = 1200 ounces
Therefore, you need: 1200/48 = 25 cans

Is this correct or Just Lucky?: The ratio of concentrate to water is 1:3 and They need 100 12oz servings to make 200 6oz servings.

So I did: 1x + 3x = 100

4x=100
x= 25

Yes, that's correct.
_________________
Math Expert
Joined: 02 Sep 2009
Posts: 39722
Re: How to solve these kind of problems? [#permalink]

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24 Dec 2013, 01:55
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