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Husain and Dino had an average (arithmetic mean) of $20 each. Dino the

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Bunuel
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Husain and Dino had an average (arithmetic mean) of $20 each. Dino the [#permalink] New post   18 Dec 2018, 00:04
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Husain and Dino had an average (arithmetic mean) of $20 each. Dino then won a cash prize, which increased the average amount of money they had to $80. If no other changes occurred, how many dollars did Dino win?

A. 40
B. 60
C. 80
D. 100
E. 120
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E
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Re: Husain and Dino had an average (arithmetic mean) of $20 each. Dino the [#permalink] New post   18 Dec 2018, 03:07
(H+D)/2 = 20
H+D = 40

(H+X+D)/2 = 80
H+X+D = 160

160-40=120

E
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Re: Husain and Dino had an average (arithmetic mean) of $20 each. Dino the [#permalink] New post   18 Dec 2018, 03:47
Bunuel wrote:
Husain and Dino had an average (arithmetic mean) of $20 each. Dino then won a cash prize, which increased the average amount of money they had to $80. If no other changes occurred, how many dollars did Dino win?

A. 40
B. 60
C. 80
D. 100
E. 120


Nice question.

Total amount Husain and Dino had before wining the cash prize = 20 *2 = 40.

After wining the cash prize AVERAGE becomes 80.

Total amount after wining cash prize = 80*2 = 160.

Value of the cash prize = 160 - 40 = 120.

E is the best answer.
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Re: Husain and Dino had an average (arithmetic mean) of $20 each. Dino the [#permalink] New post   18 Dec 2018, 08:21
Bunuel wrote:
Husain and Dino had an average (arithmetic mean) of $20 each. Dino then won a cash prize, which increased the average amount of money they had to $80. If no other changes occurred, how many dollars did Dino win?

A. 40
B. 60
C. 80
D. 100
E. 120


h + d = 40

h + (d + cash) = 160

So, The value of the cash prize is 120, Answer must be (E)
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Re: Husain and Dino had an average (arithmetic mean) of $20 each. Dino the [#permalink]
18 Dec 2018, 08:21
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