It is currently 26 Jun 2017, 08:55

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# I do not agree with the OA..

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 04 May 2006
Posts: 172
Location: paris
I do not agree with the OA.. [#permalink]

### Show Tags

12 Nov 2006, 13:48
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I do not agree with the OA...
Attachments

Snap7.jpg [ 57.66 KiB | Viewed 807 times ]

_________________

time is not on my side

SVP
Joined: 05 Jul 2006
Posts: 1747

### Show Tags

12 Nov 2006, 14:32
WEIRED
Senior Manager
Joined: 23 Jun 2006
Posts: 387

### Show Tags

12 Nov 2006, 19:17
well.... weird question (certainly not from a real GMAT prep), but it has a clear answer (A).

st1 is sufficient. if k is a multiple of 3 then t and 12 has 3 as a common factor:

k/3 is integer n. so m/4+k/3 = m/4+n = (3m+12n)/12. hence t=3m+12n.
t is a multiple of 3 and so is 12.

st2 insuff: for example m=3 k=1 (then t=13 and has only 1 as common factor with 12). m=3 k=3 has more factors. hence insufficient.

note that the questions doesn't state that t and 12 have indeed 12 as common factor. it just looks for common factors of t and 12 that are not 1 or 12. in fact, if 12 is a common factor of any two numbers, so are 2,3,4 and 6.
Manager
Joined: 04 May 2006
Posts: 172
Location: paris

### Show Tags

13 Nov 2006, 00:19
Yes Hobbit

You're right...

The fact that T is not necessarily multiple of 12 made this question hard to understand

That's why I did not agree with the OA

This question commes from 800 score

cheers
_________________

time is not on my side

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

### Show Tags

13 Nov 2006, 00:52
12 has factors 1,2,3,4,6,12.

(m/4) + (k/3) = (t/12)
3m + 4k = t

St1:
k is a multiple of 3, so 3m + 4k = 3m + 4(3)(n) where n = 1,2,3,4...etc

So 3(3m + 4n) --> which is a multipe of 3. So t and 12 will have at least 3 in common apart from 1 and 12.

St2:
m is a multiple of 3, so 3m + 4k = 3(3)j + 4k = 9j + 4k --> we can't tell since j and k has a number of possibilites.

Ans A
13 Nov 2006, 00:52
Display posts from previous: Sort by

# I do not agree with the OA..

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.