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# I sat for the test recently and scored a 44 in Quant. Here's

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Intern
Joined: 07 Jul 2005
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I sat for the test recently and scored a 44 in Quant. Here's [#permalink]

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10 Oct 2005, 16:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I sat for the test recently and scored a 44 in Quant. Here's something similar to one of the questions I think I got wrong:

.08^-5
_______
.04^-4

How do you solve? I think I can do the first couple steps, but then I get lost.
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10 Oct 2005, 17:16
(.08^-5)/(.04^-4)

oops! arithmetic seems to be my folly...

25/32, as shown by others.

Last edited by chets on 10 Oct 2005, 18:52, edited 1 time in total.
Senior Manager
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10 Oct 2005, 17:32
.08^-5 / .04^-4
= (8/100)^-5 / (4/100)^-4
= (2/25) ^-5 / (1/25)^-4
= (2^-5/5^-10) / (1/5^-8)
= (2^-5) (5^2)
= 25/32
_________________

-Vikram

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10 Oct 2005, 17:40
.08^-5
_______
.04^-4

= [- 1 / (0.08)^5] / [-1 / (0.04) ^ 4] {a^-n = - 1 / (a ^n) }

= 0.04 ^ 4 / 0.08 ^ 5
= 0.04 ^ 4 / 0.04 ^ 5 * 2 ^ 5
= 1/1.28 = 100/128 = 25/32
Director
Joined: 10 Oct 2005
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10 Oct 2005, 17:53
.08^-5
_______
.04^-4

.04^4
= _______
.08^5

= 0.04 * 0.04 * 0.04 * 0.04
_________________________
0.08 * 0.08 * 0.08 * 0.08 * 0.08

= 100 / 16 * 8

= 25 / 32
Manager
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11 Oct 2005, 07:12
Did it a bit different, same basic idea.

= (.04)^4/(.08)^5 = (4/100)^4) / (8/100)^5 = (4^4) * (100) / 8^5

this equals 2^8 *100 / 2^15 = 100/2^7 = 100/128 = 25/32

Brendan.
11 Oct 2005, 07:12
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