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# I started to get lost and ended up wasting a lot of time in

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Senior Manager
Joined: 29 Nov 2006
Posts: 318

Kudos [?]: 148 [0], given: 0

Location: Orange County, CA
I started to get lost and ended up wasting a lot of time in [#permalink]

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10 Jul 2007, 14:47
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0% (00:00) correct 0% (00:00) wrong based on 2 sessions

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I started to get lost and ended up wasting a lot of time in the process. A little light from someone?

1 / [(1/0.03) + (1/0.37)] =

(a) 0.004
(b) 0.02775
(c) 2.775
(d) 3.6036
(e) 36.036

Kudos [?]: 148 [0], given: 0

Manager
Joined: 25 Jul 2006
Posts: 97

Kudos [?]: 2 [0], given: 0

Re: PS - inverse of fractions [#permalink]

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10 Jul 2007, 15:02
misterJJ2u wrote:
I started to get lost and ended up wasting a lot of time in the process. A little light from someone?

1 / [(1/0.03) + (1/0.37)] =

(a) 0.004
(b) 0.02775
(c) 2.775
(d) 3.6036
(e) 36.036

i'd solve it by approximation:

= 1/[0.4/(0.03*0.37)] = 37*3/4000 ~ 28/1000 ~ 0.02775

Kudos [?]: 2 [0], given: 0

Manager
Joined: 22 May 2007
Posts: 121

Kudos [?]: 5 [0], given: 0

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10 Jul 2007, 15:05
1/.03 is like 33.33333 (100/3)
1/.37 = 100/37 = 2.something, almost 3

so we have 1/36 (approx)

Look for answer a little under 3 and divide by 100.

I would guess B

Kudos [?]: 5 [0], given: 0

10 Jul 2007, 15:05
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