Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 27 May 2017, 07:21

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# I thought this was an easy problem

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 48 [0], given: 0

I thought this was an easy problem [#permalink]

### Show Tags

30 Oct 2006, 19:16
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I thought this was an easy problem
Attachments

q1.gif [ 2.12 KiB | Viewed 723 times ]

Senior Manager
Joined: 05 Aug 2005
Posts: 409
Followers: 2

Kudos [?]: 60 [0], given: 0

### Show Tags

30 Oct 2006, 20:54
yes it is ...... A is the answer...

2^9/2= 2^8
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 48 [0], given: 0

### Show Tags

31 Oct 2006, 06:29
gmacvik wrote:
yes it is ...... A is the answer...

2^9/2= 2^8

d'oh!! I multiplied 3*2 instead of 3^2

thx!
Senior Manager
Joined: 13 Sep 2006
Posts: 279
Location: New York
Followers: 1

Kudos [?]: 19 [0], given: 0

### Show Tags

31 Oct 2006, 08:05
I did the same thing becuase I thought you use the "power rule here"

Power Rule

The "power rule" tells us that to raise a power to a power, just multiply the exponents. Here you see that 5^2 raised to the 3rd power is equal to 5^6.

x^mn = x^mn
(5^2)^3 = 5^6

Can some please clarify? When do use this rule instead of what was done in the original posting? Thanks so much
_________________

"Never let the fear of striking out get in your wayâ€

Senior Manager
Joined: 01 Oct 2006
Posts: 496
Followers: 1

Kudos [?]: 35 [0], given: 0

### Show Tags

31 Oct 2006, 09:46
Matrix02 wrote:
I did the same thing becuase I thought you use the "power rule here"

Power Rule

The "power rule" tells us that to raise a power to a power, just multiply the exponents. Here you see that 5^2 raised to the 3rd power is equal to 5^6.

x^mn = x^mn
(5^2)^3 = 5^6

Can some please clarify? When do use this rule instead of what was done in the original posting? Thanks so much

I too applied the same logic earlier was shocked to see the answer.
But then realised that there is bracket missing
if 2^(4-1)^2 it actually of the form x^y whereas if it was ((2^(4-1))^3) then we could use the power rule.
Hope this helps
Yogesh
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 48 [0], given: 0

### Show Tags

31 Oct 2006, 09:55
yogeshsheth wrote:
Matrix02 wrote:
I did the same thing becuase I thought you use the "power rule here"

Power Rule

The "power rule" tells us that to raise a power to a power, just multiply the exponents. Here you see that 5^2 raised to the 3rd power is equal to 5^6.

x^mn = x^mn
(5^2)^3 = 5^6

Can some please clarify? When do use this rule instead of what was done in the original posting? Thanks so much

I too applied the same logic earlier was shocked to see the answer.
But then realised that there is bracket missing
if 2^(4-1)^2 it actually of the form x^y whereas if it was ((2^(4-1))^3) then we could use the power rule.
Hope this helps
Yogesh

Yogesh, so what you're saying is this? That's sneaky!!!
Attachments

exp.GIF [ 1.46 KiB | Viewed 697 times ]

Senior Manager
Joined: 13 Sep 2006
Posts: 279
Location: New York
Followers: 1

Kudos [?]: 19 [0], given: 0

### Show Tags

31 Oct 2006, 10:00
Doe anyone have a website or rule for this case? I need to review this one in more detail for sure so I don't get fooled again. I am not to clear on the parenthesis and that works...
_________________

"Never let the fear of striking out get in your wayâ€

Senior Manager
Joined: 01 Oct 2006
Posts: 496
Followers: 1

Kudos [?]: 35 [0], given: 0

### Show Tags

31 Oct 2006, 10:25
Nsentra wrote:
yogeshsheth wrote:
Matrix02 wrote:
I did the same thing becuase I thought you use the "power rule here"

Power Rule

The "power rule" tells us that to raise a power to a power, just multiply the exponents. Here you see that 5^2 raised to the 3rd power is equal to 5^6.

x^mn = x^mn
(5^2)^3 = 5^6

Can some please clarify? When do use this rule instead of what was done in the original posting? Thanks so much

I too applied the same logic earlier was shocked to see the answer.
But then realised that there is bracket missing
if 2^(4-1)^2 it actually of the form x^y whereas if it was ((2^(4-1))^3) then we could use the power rule.
Hope this helps
Yogesh

Yogesh, so what you're saying is this? That's sneaky!!!

Nsentra
A normal exponent rule is (x^m)^n =x^(m*n) which holds true if you have if you x^m and the whole raise to n.
Thus x^(4-1)^2 !=((x^(4-1))^2).
Because if you follow PEDMAS x^(4-1)^2 =x^(3)^2=x^9
Correct me If I am wrong.
Senior Manager
Joined: 05 Aug 2005
Posts: 409
Followers: 2

Kudos [?]: 60 [0], given: 0

### Show Tags

31 Oct 2006, 18:59
OK lets go step by step

Numerator---

consider the powers of 2
4-1=3
square of 3 ===> 9

So numerator becomes 2^9

Denominator
3-2=1
hence 2^1

so the equation becomes

2^9 / 2^1

==> 2^8.

Hope I am clear now and it helps you
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 48 [0], given: 0

### Show Tags

31 Oct 2006, 19:07
anindyat wrote:
2^8

Ok.

so do you guys concur that had the problem said [2^(4-1)]^2 then the answer would be 2^5?

Just trying to finalize the whole power rule.
Senior Manager
Joined: 13 Sep 2006
Posts: 279
Location: New York
Followers: 1

Kudos [?]: 19 [0], given: 0

### Show Tags

01 Nov 2006, 07:26
Nsentra wrote:
anindyat wrote:
2^8

Ok.

so do you guys concur that had the problem said [2^(4-1)]^2 then the answer would be 2^5?

Just trying to finalize the whole power rule.

I think I am slowly (and I do mean slowly) getting this. The palcement of the paren

Nsentra - I think you meant to say [2^(4-1)]^2/2^3-2

This would equal 2^5

(2^(4-1))^2/2^3-2 = 2^5

Would (2^4-1)^2/2^3-2 also = 2^5???
_________________

"Never let the fear of striking out get in your wayâ€

01 Nov 2006, 07:26
Display posts from previous: Sort by

# I thought this was an easy problem

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.