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# I thought we need (2) statement to make inference that Y is

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Manager
Joined: 09 Nov 2006
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I thought we need (2) statement to make inference that Y is [#permalink]

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28 Apr 2007, 08:01
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I thought we need (2) statement to make inference that Y is odd?
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Current Student
Joined: 22 Apr 2007
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28 Apr 2007, 09:36
(1) x(y+5) is even.
If y is even, x is even

If y is odd, x may or may not be even
(Insuff)
-----
(2) 6y^2 + 41y + 25 is even.
So, y is odd (An even y doesn't make the expression even)
(Insuff)

So, (1) and (2) together are NOT sufficient. Is this the answer?

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VP
Joined: 08 Jun 2005
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28 Apr 2007, 12:21
mNeo wrote:
(1) x(y+5) is even.
If y is even, x is even

If y is odd, x may or may not be even
(Insuff)
-----
(2) 6y^2 + 41y + 25 is even.
So, y is odd (An even y doesn't make the expression even)
(Insuff)

So, (1) and (2) together are NOT sufficient. Is this the answer?

Good explanation, and I second (E) same logic.

where o=odd e=even

statement 1

x(y+5) is even.
e(o+5) is even.
o(o+5) is even.

x could be either o,e - insufficient

statement 2

6y^2 + 41y + 25 is even.
6o^2 + 41o + 25 is even.

y is odd but x could be either o,e - insufficient

statements 1&2

still insufficient - knowing that y is odd - still can't say if x is even (see statement 1)

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Senior Manager
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28 Apr 2007, 16:18
(1) x(y+5) = even. We cannot know for sure whether x is even, without having any info on y. Insuff => B, C, or E.

(2) 6y^2 + 41y + 25 = even. The 1st term is even in any case, therefore, for the whole exp to be even, y has to be odd (42*odd + odd = even). We donÂ´t get any info on whether x is even => Insuff => C or E.

(1&2) If y is odd => y+5 is even => we still cannot state anything about x => E.

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Intern
Joined: 23 Apr 2007
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28 Apr 2007, 21:22

S1: not sufficient, y=1 and x=1|2 return is an even integer

S2: not sufficient, no relation with x

S1 & S2: not sufficient, S2 returns even only when y odd, and multiples of even are always even, irrespective of value of x. hence x can be odd or even.

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28 Apr 2007, 21:22
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