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# I've attached my picture; my notes are in blue. Hopefully it

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Manager
Joined: 09 Feb 2006
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Location: New York, NY
I've attached my picture; my notes are in blue. Hopefully it [#permalink]

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15 Apr 2006, 15:25
00:00

Difficulty:

(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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I've attached my picture; my notes are in blue. Hopefully it makes sense.
Attachments

triangle.jpg [ 37.83 KiB | Viewed 681 times ]

Last edited by jcgoodchild on 15 Apr 2006, 15:27, edited 1 time in total.

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Manager
Joined: 09 Feb 2006
Posts: 129

Kudos [?]: 8 [0], given: 0

Location: New York, NY

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15 Apr 2006, 15:27
Sorry, I meant the answer is A in my picture. We only need to know that length. I'll edit, and repost it.

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Senior Manager
Joined: 11 Nov 2005
Posts: 325

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Location: London

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15 Apr 2006, 15:38
A.

Your explanation is quite right, but the answe should be A.

BD = BC = 6, (isoscale)

jcgoodchild wrote:
I've attached my picture; my notes are in blue. Hopefully it makes sense.

Kudos [?]: 15 [0], given: 0

Manager
Joined: 08 Feb 2006
Posts: 124

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15 Apr 2006, 16:23
how did you know that the left angle is x degree?

I understood the 180-2x and 180-4x.

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VP
Joined: 21 Sep 2003
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15 Apr 2006, 16:32
Another easy way out:

Angle BDC is an Exterior angle of the triangle BAD. And in any traingle exterior angle is equal to the sum of the interior opposite angles. Hence

2x = x + ABD
=> ABD = x
=> AD = BD = 6
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15 Apr 2006, 16:32
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