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I want to see if I got it right on my exam. It appears to be

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I want to see if I got it right on my exam. It appears to be [#permalink]

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13 Aug 2006, 00:19
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I want to see if I got it right on my exam. It appears to be a simple problem. but I got stupid at test time due to anxiety and blanked out

3^X=cube root 27*27
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Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
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13 Aug 2006, 00:23
3^x = (27*27)^(1/3)
3^x = (3^3 * 3^3)^(1/3)
3^x = (3^6)^(1/3)
3^x = 3^2
x =2
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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13 Aug 2006, 00:25
jamesrwright3 wrote:
I want to see if I got it right on my exam. It appears to be a simple problem. but I got stupid at test time due to anxiety and blanked out

3^X=cube root 27*27
or 3^x= (cube root 27)*27 ???
Re: What is the answer to this question:)   [#permalink] 13 Aug 2006, 00:25
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