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Difficulty: Sub 505 Level,   Algebra,                     
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
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Am I the only one, who does not understand why this questions is rated in OG12 as Hard? I guess I still am not a Quant-Killer, but this question seems to be quite simple and straightforward.

Thanks!
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
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bgpower
Am I the only one, who does not understand why this questions is rated in OG12 as Hard? I guess I still am not a Quant-Killer, but this question seems to be quite simple and straightforward.

Thanks!

I agree with you. From my point of view this questions is sub-600 level.
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
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To add to your point, I've noticed that in the last pages of the OG hidden among the 700+ level questions are some really easy 600 or less level questions. Anyone know why that is the case? The guide states that the questions are organized by difficulty yet in the last 40 questions, the guide has some very very easy questions.
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
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Walkabout
If 1 + 1/x = 2 - 2/x, then x =

(A) -1
(B) 1/3
(C) 2/3
(D) 2
(E) 3

We need to simplify the equation 1 + 1/x = 2 – 2/x.

We start by adding 2/x to both sides of the equation. Then we can easily solve for x. We obtain:

1 + 3/x = 2

3/x = 1

x = 3

The answer is E.
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If 1 + 1/x = 2 - 2/x, then x = [#permalink]
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Walkabout
If 1 + 1/x = 2 - 2/x, then x =

(A) -1
(B) 1/3
(C) 2/3
(D) 2
(E) 3

Another approach is to eliminate the fractions at step 1.
Given: 1 + 1/x = 2 - 2/x
Multiply both sides by x to get: x + 1 = 2x - 2
Add 2 to both sides: x + 3 = 2x
Subtract x from both sides: 3 = x

Answer: E

Originally posted by BrentGMATPrepNow on 14 Sep 2017, 07:29.
Last edited by BrentGMATPrepNow on 28 Dec 2019, 07:34, edited 1 time in total.
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
Bunuel
Walkabout
If 1 + 1/x = 2 - 2/x, then x =

(A) -1
(B) 1/3
(C) 2/3
(D) 2
(E) 3

\(1 + \frac{1}{x} = 2 - \frac{2}{x}\) --> \(\frac{1}{x}+\frac{2}{x}=1\) --> \(\frac{3}{x} = 1\) --> \(x = 3\).

Answer: E.

What did you do at the last step when you had \(\frac{3}{x} = 1\) --> \(x = 3\)?
How did you get rid of the 1 and the fraction?
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
Expert Reply
Markster
Bunuel
Walkabout
If 1 + 1/x = 2 - 2/x, then x =

(A) -1
(B) 1/3
(C) 2/3
(D) 2
(E) 3

\(1 + \frac{1}{x} = 2 - \frac{2}{x}\) --> \(\frac{1}{x}+\frac{2}{x}=1\) --> \(\frac{3}{x} = 1\) --> \(x = 3\).

Answer: E.

What did you do at the last step when you had \(\frac{3}{x} = 1\) --> \(x = 3\)?
How did you get rid of the 1 and the fraction?

Multiply both sides by x: \(\frac{3}{x}*x = 1*x\) --> \(3= x\).

Hope it's clear.
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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
Walkabout
If 1 + 1/x = 2 - 2/x, then x =

(A) -1
(B) 1/3
(C) 2/3
(D) 2
(E) 3

3/x = 1
x=3

IMO E

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Re: If 1 + 1/x = 2 - 2/x, then x = [#permalink]
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