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# If 1 < d < 2, is the tenths’ digit of the decimal

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Status: May The Force Be With Me (D-DAY 15 May 2012)
Joined: 06 Jan 2012
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If 1 < d < 2, is the tenths’ digit of the decimal  [#permalink]

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28 Apr 2012, 22:02
4
9
00:00

Difficulty:

35% (medium)

Question Stats:

73% (01:40) correct 27% (01:35) wrong based on 411 sessions

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If 1 < d < 2, is the tenths’ digit of the decimal representation of d equal to 9?

(1) d + 0.01 < 2
(2) d + 0.05 > 2

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Re: If 1 < d <2, is the tenths’ digit of the decimal  [#permalink]

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29 Apr 2012, 02:41
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If 1 < d <2, is the tenths’ digit of the decimal representation of d equal to 9?

(1) d + 0.01 <2 --> d<1.99 --> 1<d<1.99. The tenths' digit of d may or may not be 9, consider d=1.98 and d=1.1. Not sufficient.

(2) d + 0.05 > 2 --> d>1.95 --> 1.95<d<2. Each number from this range has 9 as its tenths' digit. Sufficient.

1234.567

1 - THOUSANDS
2 - HUNDREDS
3 - TENS
4 - UNITS
. - decimal point
5 - TENTHS
6 - HUNDREDTHS
7 - THOUSANDTHS

Hope it's clear.
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Re: How to solve this problem?  [#permalink]

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15 Jan 2016, 05:42
Hi =)

Try this way:

(1) d + 0.01 < 2 ; d < 1,99 It is clearly insufficient since the tenths number can be between 0 and 9

(2) d + 0.05 > 2 ; d >1,95 So you know that the tenths number must be 9 even if there is a number of infinite possibilities between 1,95 and 2

So B is sufficient!
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Re: If 1 < d < 2, is the tenths’ digit of the decimal  [#permalink]

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17 Jan 2016, 22:40
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If 1 < d < 2, is the tenths’ digit of the decimal representation of d equal to 9?

(1) d + 0.01 < 2
(2) d + 0.05 > 2

In the original condition, there is 1 variable(d), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer.
For 1), d=1.9 -> yes, 1.8 -> no, which is no and not sufficient.
For 2), if d=1.8..., d+0.05>2 is impossible. So it always has to be d=1.9..., which is yes and sufficient. Therefore, the answer is B.

-> For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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Re: If 1 < d < 2, is the tenths’ digit of the decimal  [#permalink]

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13 Mar 2016, 08:57
The thing to remember here is that Atmost carry in any division is 1
hence B is sufficent
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Re: If 1 < d < 2, is the tenths’ digit of the decimal  [#permalink]

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08 Jun 2018, 18:13
I am not able to understand how its B. If d=1.90+0.05 then its not greater than 2 . Which make it insufficient.Please explain.
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If 1 < d < 2, is the tenths’ digit of the decimal  [#permalink]

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08 Jun 2018, 22:36
I am not able to understand how its B. If d=1.90+0.05 then its not greater than 2 . Which make it insufficient.Please explain.

When picking numbers you should pick them so that they satisfy the stem and the statement you are testing. Does your example satisfy the second statement, which you are trying to test?
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Re: If 1 < d < 2, is the tenths’ digit of the decimal  [#permalink]

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09 Aug 2019, 05:12
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Re: If 1 < d < 2, is the tenths’ digit of the decimal   [#permalink] 09 Aug 2019, 05:12
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