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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of

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Math Expert V
Joined: 02 Sep 2009
Posts: 65187
If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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Difficulty:   15% (low)

Question Stats: 79% (01:41) correct 21% (02:12) wrong based on 254 sessions

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If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of x, x^2, x^3, x^4 and x^5 is equal to which of the following?

A. 12x
B. 13x
C. 14x
D. 16x
E. 20x

Kudos for a correct solution.

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Math Expert V
Joined: 02 Sep 2009
Posts: 65187
Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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Bunuel wrote:
If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of x, x^2, x^3, x^4 and x^5 is equal to which of the following?

A. 12x
B. 13x
C. 14x
D. 16x
E. 20x

Kudos for a correct solution.

OFFICIAL SOLUTION:

The average (arithmetic mean) of x, x^2, x^3, x^4 and x^5 is (x + x^2 + x^3 + x^4 + x^5)/5 = x(1 + x + x^2 + x^3 + x^4)/5 = 80x/5 = 16x.

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##### General Discussion
Intern  Joined: 01 Jan 2015
Posts: 17
Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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2
1 + x^4 + x^3 + x^2 + x = 81

multiplying by 'x' on both sides

x(1 + x^4 + x^3 + x^2 + x )= 81x

dividing by 5 we get

x+ x^2+ x^3+ x^4+x^5 = 81x/5 Approx 16x
But is approximation allowed? i don't see it mentioned in the question?
Manager  B
Joined: 12 Nov 2014
Posts: 60
Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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1 + x^4 + x^3 + x^2 + x = 81
i.e. 1 +x+ x^2+ x^3+ x^4 = 81
x+ x^2+ x^3+ x^4 = 80

x(1 +x+ x^2+ x^3) = 80
x(81-x^4) = 80

81x - x^5 = 80
x^5 = 81x -80

Now x+ x^2+ x^3+ x^4+ x^5 = 80 + 81x -80 = 81x

Average of {x, x^2, x^3, x^4, x^5} = 81x/5 ~ 16x

Ambarish
Current Student G
Joined: 21 Jan 2015
Posts: 450
Location: India
Concentration: Strategy, Marketing
GMAT 1: 620 Q48 V28 GMAT 2: 690 Q49 V35 WE: Sales (Consumer Products)
Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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1
Bunuel wrote:
If 1 + x^4 + x^3 + x^2 + x = 81, then the average (arithmetic mean) of x, x^2, x^3, x^4 and x^5 is equal to which of the following?

A. 12x
B. 13x
C. 14x
D. 16x
E. 20x

Kudos for a correct solution.

Ans: D

Solution: [x + x^2 + x^3 + x^4 + x^5]/5
Known 1 + x^4 + x^3 + x^2 + x = 81
taking x common from the first equation it becomes
=[1 + x^4 + x^3 + x^2 + x]*x/5
=81*x/5
Ans.: D
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Manager  B
Joined: 12 Nov 2014
Posts: 60
Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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NavenRk wrote:
1 + x^4 + x^3 + x^2 + x = 81

multiplying by 'x' on both sides

x(1 + x^4 + x^3 + x^2 + x )= 81x

dividing by 5 we get

x+ x^2+ x^3+ x^4+x^5 = 81x/5 Approx 16x
But is approximation allowed? i don't see it mentioned in the question?

Ohh yeah. This is a much easier way. Kudos!
I think the question meant approximate value.
Non-Human User Joined: 09 Sep 2013
Posts: 15412
Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  [#permalink]

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_________________ Re: If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of   [#permalink] 02 Apr 2020, 03:15

# If 1 + x^4 + x^3 + x^2 + x = 80, then the average (arithmetic mean) of  