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# If 10^50 - 74 is written as an integer in base 10 notation,

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If 10^50 - 74 is written as an integer in base 10 notation, [#permalink]

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30 Jun 2005, 19:32
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If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467

Senior Manager
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30 Jun 2005, 19:44
10^50 is 1 followed by 50 zeros.

10^50 - 74 = 999...926

The 9s occur 50-2 = 48 times.

Sum of digits = 48*9+6+2 = 440

C
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30 Jun 2005, 19:48
If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467

I got C.

10^50 has 1 followed by 50 zeroes.
10^50 - 74 has 48 9's with 26 at the last two places.
sum of the digits = 48*9 + 8 = 440.

HMTG.
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30 Jun 2005, 19:50
OA is C.

Thanks guys. I was trying 48*9 + 26 and coming up with no match, I guess I must call it a day.
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30 Jun 2005, 19:51
If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449

10^2-74=100-74 = 26
10^3-74=1,000-74 = 926
10^4-74=10,000-74 = 9926
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.
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10^50-74= fortyeight 9's and 26= 48X9+26= the last digit is zero so it should be 440.
Re: PS   [#permalink] 30 Jun 2005, 19:51
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