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If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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23 Aug 2012, 20:45
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If |10y - 4| > 7 and y < 1, which of the following could be y?

A. -0.8

B. -0.1

C. 0.1

D. 0

E. 1

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Last edited by

Bunuel on 24 Aug 2012, 01:27, edited 2 times in total.

Renamed the topic and edited answer choices.

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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24 Aug 2012, 01:39
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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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23 Aug 2012, 20:54
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Please, write well your question. It seems that choices C and E are the same.

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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13 Feb 2013, 11:58

why cant we get an answer by simply substituting values in the equation |10y - 4| > 7

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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13 Feb 2013, 12:31
mehasingh wrote:

why cant we get an answer by simply substituting values in the equation |10y - 4| > 7

In my opinion applying rules in modulus is much more easier than checking for multiple values.

The rules are simple.

1) !x! < a -------> -a < x < a

so if !x-a! < r then -r < x-a < r -------> a-r < x < a+r

2) !x! > a ------> either x > a or x < -a

so if !X-a! > r then either x-a > r ------> x > a+r

or x-a < -r -----> -x+a > r --------> x < a-r

Regards,

Abhijit

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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05 Jul 2013, 13:01

Bunuel wrote:

laythesmack23 wrote:

If |10y - 4| > 7 and y < 1, which of the following could be y? A. -0.8 B. -0.1 C. 0.1 D. 0 E. 1

We can simply plug answer choices less than 1 and see which one satisfies given inequality, or do the following:

\(|10y - 4| > 7\) means that either \(10y-4>7\) (when \(y>\frac{4}{10}\)) or \(-(10y-4)>7\) (when \(y\leq{\frac{4}{10}}\)).

Solve both inequalities:

\(10y-4>7\) --> \(y>1.1\). Since we are told that \(y<1\), then discard this solution.

\(-(10y-4)>7\) --> \(y<-0.3\). Only answer choice which is less than -0.3 is -0.8.

Answer: A.

Hope it's clear.

If I am not mistaken you have a typo in your explanation: 10y-4>7 shall be y>11/10 not y>4/10.

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If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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05 Jul 2013, 13:10
rhallik wrote:

Bunuel wrote:

laythesmack23 wrote:

If |10y - 4| > 7 and y < 1, which of the following could be y? A. -0.8 B. -0.1 C. 0.1 D. 0 E. 1

We can simply plug answer choices less than 1 and see which one satisfies given inequality, or do the following:

\(|10y - 4| > 7\) means that either \(10y-4>7\) (when \(y>\frac{4}{10}\)) or \(-(10y-4)>7\) (when \(y\leq{\frac{4}{10}}\)).

Solve both inequalities:

\(10y-4>7\) --> \(y>1.1\). Since we are told that \(y<1\), then discard this solution.

\(-(10y-4)>7\) --> \(y<-0.3\). Only answer choice which is less than -0.3 is -0.8.

Answer: A.

Hope it's clear.

If I am not mistaken you have typos in your explanation: 10y-4>7 shall be y>11/10 not y>4/10. The same applies to -(10y-4)...

No typo there.

When \(y>\frac{4}{10}\), then we have \(10y-4>7\) --> \(y>\frac{11}{10}\).

When \(y\leq{\frac{4}{10}}\)), then we have \(-(10y-4)>7\) --> \(y<-\frac{3}{10}\).

Hope it's clear.

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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09 Jul 2013, 16:14

If |10y - 4| > 7 and y < 1, which of the following could be y? |10y - 4| > 7 |10(-.8) - 4| > 7 |-8-4| > 7 |-12| > 7 |12| > 7 12 > 7 (A)

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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18 Jun 2017, 02:43

rhallik wrote:

Bunuel wrote:

laythesmack23 wrote:

If |10y - 4| > 7 and y < 1, which of the following could be y? A. -0.8 B. -0.1 C. 0.1 D. 0 E. 1

We can simply plug answer choices less than 1 and see which one satisfies given inequality, or do the following:

\(|10y - 4| > 7\) means that either \(10y-4>7\) (when \(y>\frac{4}{10}\)) or \(-(10y-4)>7\) (when \(y\leq{\frac{4}{10}}\)).

Solve both inequalities:

\(10y-4>7\) --> \(y>1.1\). Since we are told that \(y<1\), then discard this solution.

\(-(10y-4)>7\) --> \(y<-0.3\). Only answer choice which is less than -0.3 is -0.8.

Answer: A.

Hope it's clear.

If I am not mistaken you have a typo in your explanation: 10y-4>7 shall be y>11/10 not y>4/10.

Bunuel how are you getting the y > 4/10?

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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18 Jun 2017, 02:56
Nunuboy1994 wrote:

rhallik wrote:

Bunuel wrote:

If |10y - 4| > 7 and y < 1, which of the following could be y? A. -0.8 B. -0.1 C. 0.1 D. 0 E. 1 We can simply plug answer choices less than 1 and see which one satisfies given inequality, or do the following: \(|10y - 4| > 7\) means that either \(10y-4>7\) (when \(y>\frac{4}{10}\)) or \(-(10y-4)>7\) (when \(y\leq{\frac{4}{10}}\)). Solve both inequalities: \(10y-4>7\) --> \(y>1.1\). Since we are told that \(y<1\), then discard this solution. \(-(10y-4)>7\) --> \(y<-0.3\). Only answer choice which is less than -0.3 is -0.8. Answer: A. Hope it's clear.

If I am not mistaken you have a typo in your explanation: 10y-4>7 shall be y>11/10 not y>4/10.

Bunuel how are you getting the y > 4/10?

4/10 is a transition point for 10y-4 (transition point is a value of a variable for which expression in absolute value changes its sign).

When \(y>\frac{4}{10}\), then 10y - 4 > 0, so |10y - 4| = 10y - 4.

When \(y\leq{\frac{4}{10}}\), then 10y - 4 <= 0, so |10y - 4| = -(10y - 4).

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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01 Jul 2017, 05:21

Bunuel wrote:

laythesmack23 wrote:

If |10y - 4| > 7 and y < 1, which of the following could be y? A. -0.8 B. -0.1 C. 0.1 D. 0 E. 1

We can simply plug answer choices less than 1 and see which one satisfies given inequality, or do the following:

\(|10y - 4| > 7\) means that either \(10y-4>7\) (when \(y>\frac{4}{10}\)) or \(-(10y-4)>7\) (when \(y\leq{\frac{4}{10}}\)).

Solve both inequalities:

\(10y-4>7\) --> \(y>1.1\). Since we are told that \(y<1\), then discard this solution.

\(-(10y-4)>7\) --> \(y<-0.3\). Only answer choice which is less than -0.3 is -0.8.

Answer: A.

Hope it's clear.[/quo

How can u assume that the answer is -0.8 when get the solved answered as -0.3??

please explain @bunnel

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If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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01 Jul 2017, 07:44

Bunuel wrote:

shinrai15 wrote:

How can u assume that the answer is -0.8 when get the solved answered as -0.3?? please explain @bunnel

We did not get that y = -0.3. We got that y < -0.3 (y is LESS than 0.3). -0.8 IS LESS than -0.3, so y could be -0.8

Thank you @bunnel for clarifying..

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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01 Jul 2017, 08:08

Solve the equation by taking out the modulus so we get 10y - 4 > 7 or 10y - 4 < -7.

On solving the equations as per the condition that y <0 we get that y < -3/10 I.e. y < -0.3; thus the only option that fits is -0.8, hence option A

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Re: If |10y-4| > 7 and y < 1, which of the following could be y? [#permalink ]

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02 Jul 2017, 01:20

feellikequitting wrote:

If |10y - 4| > 7 and y < 1, which of the following could be y? A. -0.8 B. -0.1 C. 0.1 D. 0 E. 1

Plug-in answer choices into inequality

Let y = -0.8...........|10* -0.8 - 4| > 7.............|-12| > 7.......12 > 7

Answer: A

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Re: If |10y-4| > 7 and y < 1, which of the following could be y?
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