It is currently 23 Jun 2017, 10:42

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If 12 ounces of a strong vinegar solution are diluted with

Author Message
TAGS:

### Hide Tags

Manager
Joined: 14 Apr 2010
Posts: 222
If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

19 Jul 2010, 00:07
3
KUDOS
13
This post was
BOOKMARKED
00:00

Difficulty:

55% (hard)

Question Stats:

67% (02:49) correct 33% (02:02) wrong based on 430 sessions

### HideShow timer Statistics

If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

A. 19.3%
B. 17%
C. 16.67%
D. 15.5%
E. 12.5%
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 39609

### Show Tags

19 Jul 2010, 00:19
1
KUDOS
Expert's post
6
This post was
BOOKMARKED
bibha wrote:
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

19.3%
17%
16.67%
15.5%
12.5%

Let the concentration of the original solution be $$x%$$.

$$3%$$ of vinegar in $$50+12=62$$ ounces of vinegar solution came from $$12$$ onces of $$x%$$ strong vinegar solution (as in 50 ounces of water there is no vinegar at all), so: $$12*x=0.03(12+50)$$ --> $$x=0.155=15.5%$$.

_________________
Manager
Joined: 12 Jun 2007
Posts: 125

### Show Tags

19 Jul 2010, 00:58
3
KUDOS
2
This post was
BOOKMARKED
i will go with Option D,

New mixture = 62 ounces, which means 1.86 ounce for vinegar

Vinegar source is only from solution, so 1.86 of 12 ounce

which means 15.5 % of the solution
Intern
Joined: 11 Jul 2012
Posts: 46
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

27 Sep 2012, 13:40
1
KUDOS
1
This post was
BOOKMARKED
Let X be the quantity of non-vinegar in the strong vvinegar solution
Thus vinegar quantity will be 12 - X
When 50 ounces of water were added the percentage of vinegar becomes 3%, thus (12 - X)/62 = 3/100
From this equation X = 10.14

Brother Karamazov
Intern
Joined: 13 Sep 2012
Posts: 1
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

27 Sep 2012, 14:46
V1*S1=V2*S2.
V1=12, S1=S1;
V2=(50+12)=62, S2=3%.
THEN, S1= (62*3%)/12=0.155=15.5%
Intern
Joined: 02 May 2013
Posts: 24
WE: Engineering (Aerospace and Defense)
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

13 May 2013, 23:16
Vinegar Quantity = 12 ounces(x% of concentration) = percentage of vinegar in water vinegar mixture
i.e, 12*x/100 = 3*(50+12)/100
x=15.5 % Original vinegar concentration
Manager
Joined: 01 Jan 2013
Posts: 63
Location: India
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

20 Sep 2013, 14:28
bibha wrote:
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

A. 19.3%
B. 17%
C. 16.67%
D. 15.5%
E. 12.5%

This is a type of question where homogenous solution(Water) is mixed with a mixture
Therefore
concentration is inversely proportional to volume
i.e Concentation(final) X Volume(Final) = Concentration(initial) X volume(initial)
0.3 X 62 = Concentration(initial) X 12
Concentration (initial) = 15.5%
Hence D
Intern
Joined: 29 Jan 2013
Posts: 44
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

20 Sep 2013, 19:06
I am not sure where i going wrong.

Let the total volume is v ounces, hence we need to find out (12/v)*100.
When 50 ounces of water is added the total volume is increased to V+50

Given (12/v+50) * 100 = 3 on solving we get v=350.
hence 12/350 * 100 = 3.4

Can some one tell me whats wrong in this way?
Intern
Joined: 29 Jan 2013
Posts: 44
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

20 Sep 2013, 19:12
i am not sure where i am going wrong.

Let V be the initial volume of solution and we need to find (12/v)*100 and there by v

After adding 50 ounces of water, the concentration is 3% i.e

12/(v+50) * 100 = 3=> v= 350

so 12/350 * 100 = 3.4

Can some one tell where i am going wrong?
Math Expert
Joined: 02 Sep 2009
Posts: 39609
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

21 Sep 2013, 03:15
I am not sure where i going wrong.

Let the total volume is v ounces, hence we need to find out (12/v)*100.
When 50 ounces of water is added the total volume is increased to V+50

Given (12/v+50) * 100 = 3 on solving we get v=350.
hence 12/350 * 100 = 3.4

Can some one tell me whats wrong in this way?

What has the volume has to do with the problem?

50 ounces of 0% solution (water) is added to 12 ounces of x% solution, resulting in 62 ounces of 3% solution. The question asks to find the value of x.

Check the solution here: if-12-ounces-of-a-strong-vinegar-solution-are-diluted-with-97494.html#p751157

Hope it helps.
_________________
Manager
Joined: 23 May 2013
Posts: 126
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

20 Oct 2013, 00:01
1
KUDOS
Solved it through allegation rule.
Vinegar in Strong solution = x
Vinegar in water = 0

By allegation rule

3/(x-3) = 12/50 (12/50 coz, they are mixed in the same proportions)
150 = 12x-36
12x = 186
x= 15.5

So the initial conc of vinegar was 15.5%
_________________

“Confidence comes not from always being right but from not fearing to be wrong.”

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15926
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

23 Mar 2015, 06:53
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Director
Joined: 23 Jan 2013
Posts: 586
Schools: Cambridge'16
If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

29 Jul 2015, 00:56
x/x+(12-x)+50=1.86/62, where x-vinegar, 12-x is non-vinegar

x/62=1.86/62, x=1.86, so (1.86/12)*100=15.5%

OR

100x/62=3 => x=1.86, (1.86/12)*100=15.5%

D
Director
Joined: 05 Mar 2015
Posts: 927
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

02 May 2016, 10:20
bibha wrote:
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

A. 19.3%
B. 17%
C. 16.67%
D. 15.5%
E. 12.5%

Initially the volume=12 ounces
later we add 50ounces water to get final volume =50+12 =62 ounces.
Concentration of vinegar in final solution=3%
As amount of vinegar is same as before or after dilution
A=C*V
12*x%=62*3%
X=15.5%
Ans D
Director
Joined: 07 Dec 2014
Posts: 708
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

18 Jul 2016, 20:54
let x=% vinegar in original solution
12x=.03(12+50)
x=1.86/12=15.5%
Senior Manager
Joined: 20 Feb 2015
Posts: 388
Concentration: Strategy, General Management
Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

### Show Tags

20 Jul 2016, 03:57
62 ounce = 3% vinegar solution, which is 1.86 ounce of vinegar
vinegar in original solution=
(1.86/12)*100 = 15.5%
Re: If 12 ounces of a strong vinegar solution are diluted with   [#permalink] 20 Jul 2016, 03:57
Similar topics Replies Last post
Similar
Topics:
8 John has 3 solutions: a 12% saline solution, a 8% vinegar solution, an 2 20 Mar 2017, 02:02
2 A chemist mixes a 12-ounce solution that is 45% acid with 8 ounces of 2 21 Jan 2017, 15:21
1 A container holding 12 ounces of a solution that is 1 part alcohol to 2 17 Dec 2015, 09:53
17 Five gallons of a solution of vinegar and water with 8% vinegar is to 6 27 Sep 2016, 02:26
3 John has 3 solutions: a 12% saline solution, a 8% vinegar 10 09 Apr 2016, 19:06
Display posts from previous: Sort by