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# If 2 4n^2+ 7 = 39, what is the value of n ?

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If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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19 Oct 2017, 11:56
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84% (00:29) correct 16% (01:07) wrong based on 43 sessions

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If 2$$\sqrt{4n^2}$$ + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2$$\sqrt{2}$$
(D) 2
(E) $$\sqrt{2}$$
[Reveal] Spoiler: OA

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Director
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Re: If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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19 Oct 2017, 13:24
If 2$$\sqrt{4n^2}$$ + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2$$\sqrt{2}$$
(D) 2
(E) $$\sqrt{2}$$

$$=> 2*2n=39-7$$

or $$n=8$$

Option A

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Re: If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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19 Oct 2017, 14:03
If 2$$\sqrt{4n^2}$$ + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2$$\sqrt{2}$$
(D) 2
(E) $$\sqrt{2}$$

2$$\sqrt{4n^2}$$ + 7 = 39
2$$\sqrt{4n^2}$$ = 32
$$\sqrt{4n^2}$$ = 16
2n = 16
n = 8

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Re: If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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24 Oct 2017, 06:46
If 2$$\sqrt{4n^2}$$ + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2$$\sqrt{2}$$
(D) 2
(E) $$\sqrt{2}$$

We can simplify the given equation:

2√(4n^2) = 32

√(4n^2) = 16

4n^2 = 16^2

√4n^2 = √16^2

2n = 16

n = 8

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Re: If 2 4n^2+ 7 = 39, what is the value of n ?   [#permalink] 24 Oct 2017, 06:46
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