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If 2 4n^2+ 7 = 39, what is the value of n ?

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If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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New post 19 Oct 2017, 11:56
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Question Stats:

84% (00:29) correct 16% (01:07) wrong based on 43 sessions

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If 2\(\sqrt{4n^2}\) + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2\(\sqrt{2}\)
(D) 2
(E) \(\sqrt{2}\)
[Reveal] Spoiler: OA

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Re: If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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New post 19 Oct 2017, 13:24
SajjadAhmad wrote:
If 2\(\sqrt{4n^2}\) + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2\(\sqrt{2}\)
(D) 2
(E) \(\sqrt{2}\)


\(=> 2*2n=39-7\)

or \(n=8\)

Option A

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Re: If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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New post 19 Oct 2017, 14:03
SajjadAhmad wrote:
If 2\(\sqrt{4n^2}\) + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2\(\sqrt{2}\)
(D) 2
(E) \(\sqrt{2}\)



2\(\sqrt{4n^2}\) + 7 = 39
2\(\sqrt{4n^2}\) = 32
\(\sqrt{4n^2}\) = 16
2n = 16
n = 8

Answer A
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Re: If 2 4n^2+ 7 = 39, what is the value of n ? [#permalink]

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New post 24 Oct 2017, 06:46
SajjadAhmad wrote:
If 2\(\sqrt{4n^2}\) + 7 = 39, what is the value of n ?

(A) 8
(B) 4
(C) 2\(\sqrt{2}\)
(D) 2
(E) \(\sqrt{2}\)


We can simplify the given equation:

2√(4n^2) = 32

√(4n^2) = 16

4n^2 = 16^2

√4n^2 = √16^2

2n = 16

n = 8

Answer: A
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Re: If 2 4n^2+ 7 = 39, what is the value of n ?   [#permalink] 24 Oct 2017, 06:46
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If 2 4n^2+ 7 = 39, what is the value of n ?

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