It is currently 20 Oct 2017, 14:58

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0

Author Message
Manager
Joined: 28 Aug 2004
Posts: 205

Kudos [?]: 2 [0], given: 0

If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 [#permalink]

### Show Tags

20 Jul 2005, 07:06
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If -2*x>3*y, is x negative?

(1) y>0
(2) 2*x+5*y-20=0

Kudos [?]: 2 [0], given: 0

Director
Joined: 03 Nov 2004
Posts: 850

Kudos [?]: 57 [0], given: 0

### Show Tags

20 Jul 2005, 09:20
I will go with A

x < (-3/2)y. In order to satisfy this condition, x will be less than zero, when y is greater than zero and x may be less than zero or greater than zero, when y is less than zero.

Statement 1: Since y is greater than 0, x should always be less than zero.
Statement 2: 2x + 5y = 20, substituting x < (-3/2)y in this we get different values for y, and so x can be both positive or negative.

Kudos [?]: 57 [0], given: 0

Manager
Joined: 21 Jun 2004
Posts: 235

Kudos [?]: 5 [0], given: 0

### Show Tags

20 Jul 2005, 09:42
A

if y > 0, then right side of A is positive. For the left side to be greater than the right side, it too needs to be positive, which means x needs to be negative.

B is insufficient.
2*x+5*y-20=0
x can be 0, +ve or -ve and we can find a corresponding value for y to fit in the equation .

Kudos [?]: 5 [0], given: 0

Senior Manager
Joined: 30 May 2005
Posts: 275

Kudos [?]: 44 [0], given: 0

### Show Tags

20 Jul 2005, 17:07
another A

ST1 SINCE y>0
and -2*x>3*y
3Y IS APOSITIVE NUMBER
-2x to be greater than a positive number
x has to be negative -2 *-x will give A POSITIVE NUMBER bigger than this other positive number 3y sufficient yes

st2 TWO variables one equation insufficient

Kudos [?]: 44 [0], given: 0

Manager
Joined: 28 Aug 2004
Posts: 205

Kudos [?]: 2 [0], given: 0

### Show Tags

21 Jul 2005, 02:24
nope...

Kudos [?]: 2 [0], given: 0

Director
Joined: 13 Nov 2003
Posts: 788

Kudos [?]: 61 [0], given: 0

Location: BULGARIA

### Show Tags

21 Jul 2005, 07:18
think it should be D) it is obvious why A is OK,Let's see B) From B) X=(20-5y)/2. When we substitute in the stem then we get that Y>10 or B) by itself is sufficient

Kudos [?]: 61 [0], given: 0

Current Student
Joined: 28 Dec 2004
Posts: 3350

Kudos [?]: 319 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

21 Jul 2005, 08:08
it should be D

1) straight forward...

2) we have 2 equations, 2 unkowns...sufficient....

D it is..

Kudos [?]: 319 [0], given: 2

Senior Manager
Joined: 17 Apr 2005
Posts: 372

Kudos [?]: 30 [0], given: 0

Location: India

### Show Tags

21 Jul 2005, 09:07
Dan wrote:
If -2*x>3*y, is x negative?

(1) y>0
(2) 2*x+5*y-20=0

Picked D.

A) sufficient
B) given 2x + 3y < 0,
consider ,
2*x+5*y-20=0
or 2y - 20 > 0
or y > 10.

HMTG.

Kudos [?]: 30 [0], given: 0

Senior Manager
Joined: 04 May 2005
Posts: 278

Kudos [?]: 79 [0], given: 0

Location: CA, USA

### Show Tags

21 Jul 2005, 21:01
D for me

with -2*x>3*y
-> y <(-2/3)*x

(1) y>0 => alone is sufficient

(2) 2*x+5*y-20=0
plug in y<(-2/3)*x, we get:

2*x + 5*(-2/3)*x - 20 > 0

therefore x < -15 => alone is sufficient

Kudos [?]: 79 [0], given: 0

21 Jul 2005, 21:01
Display posts from previous: Sort by