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# If (20!*20!)/20^n is an integer

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Manager
Joined: 18 Oct 2018
Posts: 91
Location: India
Concentration: Finance, International Business
GMAT 1: 710 Q50 V36
GPA: 4
WE: Business Development (Retail Banking)
If (20!*20!)/20^n is an integer  [#permalink]

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07 Jan 2019, 09:52
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Question Stats:

57% (01:32) correct 43% (01:42) wrong based on 102 sessions

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If (20!*20!)/20^n is an integer, what is the largest possible value of n?

A. 6
B. 8
C. 10
D. 11
E. 12

Please Press Kudos if you find the question worth it.
Manager
Joined: 08 Oct 2018
Posts: 61
Location: India
GPA: 4
WE: Brand Management (Health Care)
If (20!*20!)/20^n is an integer  [#permalink]

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Updated on: 07 Jan 2019, 23:10
2
anshkool4u wrote:
If (20!*20!)/20^n is an integer, what is the largest possible value of n?

A. 6
B. 8
C. 10
D. 11
E. 12

Please Press Kudos if you find the question worth it.

$$\frac{(20!*20!)}{20^n}$$
Greatest possible value of 'n' for which the fraction will be an integer means finding the total number of "20s" in 20! x 20!

20 = 5 x $$2^2$$
Since the number of 2s will always be more than number of 5s, we calculate only the number of 5s in 20!

Number of 5s in 20! = $$\frac{20}{5}$$ = 4
Since there are 2 20! in numerator, the number of 5s in 20^n will be 2x4 = 8

Hence option B.

Alternate Method

$$20!*20! = (20!)^2$$
$$\frac{(20!)^2}{20^n}$$ is an integer and value of 'n' will be the same as the maximum number of 20s in $$(20!)^2$$

Number of 20s means finding number of 5s.
Therefore, 20/5 = 4
So n=4
i.e $$20^4$$
Number of 5s (or 20s) in $$(20!)^2 = (20^4)^2 = 20^8$$

i.e n=8. Option B
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Originally posted by Darshi04 on 07 Jan 2019, 10:53.
Last edited by Darshi04 on 07 Jan 2019, 23:10, edited 1 time in total.
Manager
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Posts: 60
Re: If (20!*20!)/20^n is an integer  [#permalink]

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07 Jan 2019, 12:14
Finding out number of 5's in 20! Will give us 4.
And as 20! Is given twice we take 4+4=8.
Hence, B.

Why we look for 5 and not 2?
→ because there will always be a greater no of 2's so we look for exact number of 5's to know the perfect answer.

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Re: If (20!*20!)/20^n is an integer  [#permalink]

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09 Jan 2020, 05:02
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Re: If (20!*20!)/20^n is an integer   [#permalink] 09 Jan 2020, 05:02
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# If (20!*20!)/20^n is an integer

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