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# if 200 lb of a mixture contain 80% husk and 20%sand. Then

Author Message
Current Student
Joined: 28 Dec 2004
Posts: 3357
Location: New York City
Schools: Wharton'11 HBS'12
if 200 lb of a mixture contain 80% husk and 20%sand. Then [#permalink]

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21 Jun 2008, 09:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

if 200 lb of a mixture contain 80% husk and 20%sand. Then how much husk needs to be extracted in order to have 75% concentration of Husk?

1/4
20/3
1/2
40
60
Director
Joined: 27 May 2008
Posts: 541

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21 Jun 2008, 09:24
if x lb of hust is removed

cureet husk = 80% of 200 = 160

160 - x = (200-x) * 75/100

x=40
Current Student
Joined: 28 Dec 2004
Posts: 3357
Location: New York City
Schools: Wharton'11 HBS'12

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21 Jun 2008, 09:35
my approach is similar

(80-x)/20=75/25
80-x=60
x=20

2*20=40..
Re: ratio problem   [#permalink] 21 Jun 2008, 09:35
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