Bunuel wrote:
If \(243^x*463^y =n\), where x and y are positive integers, what is the units digit of n?
The units digit of \(243^x\) is the same as the units digit of \(3^x\) and similarly the units digit of \(463^y\) is the same as the units digit of \(3^y\), so the units digit of \(243^x*463^y\) equals to the units digit of \(3^x*3^y=3^{x+y}\). So, knowing the value of \(x+y\) is sufficient to determine the units digit of \(n\).
(1) \(x + y = 7\). Sufficient. (As cyclicity of units digit of \(3\) in integer power is \(4\), units digit of \(3^7\) would be the same as of units digit of \(3^3\) which is \(7\))
(2) \(x=4\). No info about \(y\). Not sufficient.
Answer: A.
Hope it helps.
BunuelThanks Bunuel, this is one easy way out.
I found one long way.
Units digit for 3 -
3
9
7
1 -- cycle
A. x + y = 7 then x y combination
x = 0 y 7 unit digit 1 and 7
x 1 y 6 unit digit 3 and 9
x 2 y 5 unit digit 9 and 3
x 3 y 4 unit digit 7 and 1
in all cases unit digit is 7