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explanation [#permalink]
Can you explain me your reasoning step by step very slowly?
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Re: explanation [#permalink]
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marcodonzelli wrote:
Can you explain me your reasoning step by step very slowly?


No. less than 2 min.

Another way, even easier and faster:

one line has 24 intersections. We have 25 line. Therefore the number of intersection points is 24*25/2 (2- because we count twice the same point)
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[#permalink]
The question should state that the lines are of infinite length otherwise the answer could be anything.
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alexperi wrote:
The question should state that the lines are of infinite length otherwise the answer could be anything.


see difference between "line" and "line segment" in geometry
https://www.mathleague.com/help/geometry/basicterms.htm or
https://math.about.com/library/weekly/aa031503a.htm
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Re: Permutation & combination [#permalink]
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Amardeep Sharma wrote:
If 25 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect?

A 2300
B 600
C 250
D 300
E none of these

Please explaing for me to understand the concept

Amar


I got D:
since any 2 lines has 1 intersect with each other, we need to find the number of ways to choose 2 out of 25: 25C2=25*24/2=300.
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Re: Permutation & combination [#permalink]
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If 25 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect?

A 2300
B 600
C 250
D 300
E none of these

Soln: Since no three are concurrent, hence any point that is formed by two different lines are distinct.
The first line intersects each of the other 24 lines at 24 points. => statement 1
The second line intersects each of the other 23 lines at 23 points. The point with first line has already been counted in the statement no.1.
The third line intersects each of the other 22 lines at 22 points
and so on.

Thus total number of points is
= 24 + 23 + 22 + ... + 1
= 24 * 25/2
= 300

Ans is D
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Re: If 25 lines are drawn in a plane such that no two of them [#permalink]
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Amardeep Sharma wrote:
If 25 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect?

A. 2300
B. 600
C. 250
D. 300
E. none of these


Every pair of two lines causes one Point of Intersection

So the No. of ways in which pairs of two lines out of 25 lines can be selected in different ways = 25C2 = 300

Answer: Option D
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Re: If 25 lines are drawn in a plane such that no two of them [#permalink]
Rule: unless 2 lines are parallel, the 2 lines drawn in a plane will eventually always intersect at one point

Since none of the 25 lines are parallel to each other, all 25 lines will intersect with one another at one point in the plane


Line 1 + Line 2 ———-> will create 1 intersection point

When line 3 is drawn, it will intersect with line 1 and line 2———-> +2 more intersection points

When line 4 is drawn, it will intersect with line 1 and line 2 and line 3 ———> +3 more intersection points


The pattern will continue until:

When line 25 is drawn ———> +24 more intersection points


We just need to sum the consecutive positive integers from 1 through 24:

= (24) (1 + 24) / 2

= 12 * 25


300

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Re: If 25 lines are drawn in a plane such that no two of them [#permalink]
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