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If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of

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If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of [#permalink]

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15 May 2017, 12:29
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If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of w, y, and z?

A. 15
B. 25
C. 50
D. 100
E. It cannot be determined from the information given.

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Joined: 07 Mar 2016
Posts: 46
Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of [#permalink]

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15 May 2017, 12:40
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Combining the given equations: 4w+4y+4z=180

180/12=15

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Joined: 07 Jul 2012
Posts: 335
Location: India
Concentration: Finance, Accounting
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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of [#permalink]

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16 May 2017, 00:19
1
2w+y=47-----------(1)
3y+z=112----------(2)
2w+3z=21---------(3)

Add equation (1), (2) and (3)

4x+4y+4z= 112+47+21
4(x+y+z)= 180
(x+y+z)= $$\frac{180}{4}$$= 45

So average of X, y and z= $$\frac{45}{3}$$= 15

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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of [#permalink]

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19 May 2017, 06:20
If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of w, y, and z?

A. 15
B. 25
C. 50
D. 100
E. It cannot be determined from the information given.

We can add the three equations 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, and we have:

4w + 4y + 4z = 47 + 112 + 21

4w + 4y + 4z = 180

Dividing by 4, we have:

w + y + z = 45

Thus, the average of w, y, and z is 45/3 = 15.

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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of   [#permalink] 19 May 2017, 06:20
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