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If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of

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If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of  [#permalink]

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New post 15 May 2017, 12:29
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If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of w, y, and z?

A. 15
B. 25
C. 50
D. 100
E. It cannot be determined from the information given.

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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of  [#permalink]

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New post 15 May 2017, 12:40
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Combining the given equations: 4w+4y+4z=180

180/12=15

Answer Choice "A"
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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of  [#permalink]

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New post 16 May 2017, 00:19
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2w+y=47-----------(1)
3y+z=112----------(2)
2w+3z=21---------(3)

Add equation (1), (2) and (3)

4x+4y+4z= 112+47+21
4(x+y+z)= 180
(x+y+z)= \(\frac{180}{4}\)= 45

So average of X, y and z= \(\frac{45}{3}\)= 15

Answer: A.

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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of  [#permalink]

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New post 19 May 2017, 06:20
SajjadAhmad wrote:
If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of w, y, and z?

A. 15
B. 25
C. 50
D. 100
E. It cannot be determined from the information given.


We can add the three equations 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, and we have:

4w + 4y + 4z = 47 + 112 + 21

4w + 4y + 4z = 180

Dividing by 4, we have:

w + y + z = 45

Thus, the average of w, y, and z is 45/3 = 15.

Answer: A
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Re: If 2w + y = 47, 3y + z = 112, and 2w + 3z = 21, what is the average of &nbs [#permalink] 19 May 2017, 06:20
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