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If 2x + 3 = y + 1/y, then x + y = (1) x = –1/4 (2) y = 2

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If 2x + 3 = y + 1/y, then x + y = (1) x = –1/4 (2) y = 2  [#permalink]

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New post 21 Sep 2019, 23:54
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If \(2x + 3 = y + \frac{1}{y,}\) then \(x + y =\)

(1) \(x = –\frac{1}{4}\)

(2) \(y = 2\)

Source: Nova GMAT

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If 2x + 3 = y + 1/y, then x + y = (1) x = –1/4 (2) y = 2  [#permalink]

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New post 22 Sep 2019, 19:27
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If \(2x + 3 = y + \frac{1}{y,}\) then \(x + y =\)

If you are short of time, we have one equation given, we require one more equation to answer..
If we know the value of y, we can find x, as x does not have any power. However if we know the value of x, there is a likelihood that we do not get the answer, as we will have a quadratic equation with y^2, so y could have two values...
Short of time, mark B without solving


(1) \(x = –\frac{1}{4}\)
\(2x + 3 = y + \frac{1}{y}\)=\(2*-(\frac{1}{4}) + 3 = y + \frac{1}{y}\)=\(\frac{5}{2} = y + \frac{1}{y}\)..
\(2y^2-5y+2=0.....2y(y-2)-(y-2)=0....(2y-1)(y-2)=0\), so y could be 2 or 1/2
Insuff

(2) \(y = 2\)
\(2x + 3 = y + \frac{1}{y,}\)=\(2x + 3 = 2+ \frac{1}{2}=\frac{5}{2}...2x=\frac{-1}{2}...x=\frac{-1}{4}\)
Thus, \(x+y=2+(\frac{-1}{4})=\frac{7}{4}\)
Suff

B
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If 2x + 3 = y + 1/y, then x + y = (1) x = –1/4 (2) y = 2   [#permalink] 22 Sep 2019, 19:27
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If 2x + 3 = y + 1/y, then x + y = (1) x = –1/4 (2) y = 2

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