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If 2x = 3y = 4z = 20, then 12xyz =
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20 Jun 2024, 13:43
20 Jun 2024, 13:43
2
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Difficulty:
5%
(low)
Question Stats:
100% (00:44) correct
0% (00:00) wrong based on 5 sessions
If 2x = 3y = 4z = 20, then 12xyz =
A. 16,000
B. 8,000
C. 4,000
D. 800
E. 10
A. 16,000
B. 8,000
C. 4,000
D. 800
E. 10
Re: If 2x = 3y = 4z = 20, then 12xyz =
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20 Jun 2024, 16:28
20 Jun 2024, 16:28
2x = 20 -> x = 10
3y = 20 -> y = 20/3
4z = 20 -> z = 5
12xyz = 12(10)(20/3)(5) = (4)(1000) = 4,000
Option C
Posted from my mobile device
3y = 20 -> y = 20/3
4z = 20 -> z = 5
12xyz = 12(10)(20/3)(5) = (4)(1000) = 4,000
Option C
Posted from my mobile device
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Posts: 13991
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If 2x = 3y = 4z = 20, then 12xyz =
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22 Jun 2024, 04:00
22 Jun 2024, 04:00
Expert Reply
Official Explanation
One approach you can use to solve this problem is to find the values of all three variables.
\(2x = 20,\) or \(x = 10\)
\(3y = 20,\) or \(y= \frac{20}{3}\)
\(4z = 20,\) or \(z = 5\)
So \(12xyz=12(10)(\frac{20}{3})(5) = 4000\), and the correct answer is Choice C.
Another approach you can use to solve this problem is to notice it.
\(12xyz= \frac{(2x)(3y)(4z)}{2} = \frac{(20)(20)(20)}{2} = 4,000\)
Therefore, the correct answer is Choice C.
Answer: C
One approach you can use to solve this problem is to find the values of all three variables.
\(2x = 20,\) or \(x = 10\)
\(3y = 20,\) or \(y= \frac{20}{3}\)
\(4z = 20,\) or \(z = 5\)
So \(12xyz=12(10)(\frac{20}{3})(5) = 4000\), and the correct answer is Choice C.
Another approach you can use to solve this problem is to notice it.
\(12xyz= \frac{(2x)(3y)(4z)}{2} = \frac{(20)(20)(20)}{2} = 4,000\)
Therefore, the correct answer is Choice C.
Answer: C
