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If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)

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If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)  [#permalink]

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New post 15 Jul 2019, 23:51
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Re: If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)  [#permalink]

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New post 16 Jul 2019, 08:19
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Let us assume x = 1 and y = 1

Numerator = \(\frac{5-4}{2-1}\) = \(\frac{1}{1}\) = 1
Denominator = 3/1-2 + 5 = -3+5 = 2

Therefore. \(\frac{numerator}{denominator}\) = \(\frac{1}{2}\) (the answer is A)
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Re: If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)  [#permalink]

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New post 16 Jul 2019, 00:06
Bunuel wrote:
If \(2x \neq y\) and \(5x \neq 4y\), what is the value of \(\frac{\frac{5x-4y}{2x-y}}{\frac{3y}{y-2x} + 5}\) ?

A. \(\frac{1}{2}\)

B. \(\frac{3}{2}\)

C. \(\frac{5}{2}\)

D. \(\frac{7}{2}\)

E. \(\frac{9}{2}\)



\(\frac{\frac{5x-4y}{2x-y}}{\frac{3y}{y-2x} + 5}\)
=\(\frac{\frac{5x-4y}{2x-y}}{\frac{8y-10x}{y-2x}}\)
=\(\frac{\frac{5x-4y}{2x-y}}{\frac{10x-8y}{2x-y}}\)
=\(\frac{5x-4y}{10x-8y}\)
=\(\frac{1}{2}\)

IMO A
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Re: If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)  [#permalink]

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New post 16 Jul 2019, 00:08
Bunuel wrote:
If \(2x \neq y\) and \(5x \neq 4y\), what is the value of \(\frac{\frac{5x-4y}{2x-y}}{\frac{3y}{y-2x} + 5}\) ?

A. \(\frac{1}{2}\)

B. \(\frac{3}{2}\)

C. \(\frac{5}{2}\)

D. \(\frac{7}{2}\)

E. \(\frac{9}{2}\)



\(\frac{\frac{5x-4y}{2x-y}}{\frac{3y}{y-2x} + 5}\)
\(=\frac{\frac{5x-4y}{2x-y}}{\frac{8y-10x}{y-2x}}\)
\(=\frac{\frac{5x-4y}{2x-y}}{\frac{10x-8y}{2x-y}}\)
\(=\frac{5x-4y}{10x-8y}\)
\(=\frac{1}{2}\)



IMO A
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Re: If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)  [#permalink]

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New post 16 Jul 2019, 00:35
This is A when we reduce the equation we get y - 2x which has to be replaced with -(2x-y) and the denominator similarly is replaced with -2 (5x- 4y) this brings us to 1/2 A
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Re: If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)  [#permalink]

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New post 16 Jul 2019, 11:36
bebs wrote:
Let us assume x = 1 and y = 1

Numerator = \(\frac{5-4}{2-1}\) = \(\frac{1}{1}\) = 1
Denominator = 3/1-2 + 5 = -3+5 = 2

Therefore. \(\frac{numerator}{denominator}\) = \(\frac{1}{2}\) (the answer is A)

I followed the same approach
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Re: If 2x ≠ y and 5x ≠ 4y, what is the value of (5x - 4y)/(2x - y)/(3y/y-)   [#permalink] 16 Jul 2019, 11:36
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