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Difficulty:
Question Stats:
79% (01:29) correct 21% (01:50) wrong based on 284 sessionsCase-1: If a > 0
Case-2: If -7/3 < a < 0
Case-3: If -7/3 > a
i.e. \(a ≤ -\frac{19}{5}\) or \(a ≥ 5\)
We will have two cases | |
-Case 1: 3a + 7 ≥ 0 => 3a ≥ -7 => a ≥ \(\frac{-7}{3}\) => |3a + 7| = 3a + 7 => 3a + 7 ≥ 2a + 12 => a ≥ 5 And our condition was a ≥ \(\frac{-7}{3}\) => a ≥ 5 is a SOLUTION | -Case 2: 3a + 7 < 0 => 3a < -7 => a < \(\frac{-7}{3}\) ~ -2.3 => |3a + 7| = -(3a + 7) => -3a - 7 ≥ 2a + 12 => 5a ≤ -19 => a ≤ \(\frac{-19}{5}\) (=-3.8) And our condition was a < \(\frac{-7}{3}\) => a ≤ \(\frac{-19}{5}\) is a SOLUTION |
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