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Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value

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Math Expert V
Joined: 02 Sep 2009
Posts: 58371
If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value  [#permalink]

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22 00:00

Difficulty:   75% (hard)

Question Stats: 65% (03:12) correct 35% (03:07) wrong based on 178 sessions

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Tough and Tricky questions: Algebra.

If 3x – 2y – z = 32 + z and $$\sqrt{3x} - \sqrt{2y + 2z} = 4$$, what is the value of x + y + z?

(A) 3
(B) 9
(C) 10
(D) 12
(E) 14

Kudos for a correct solution.

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Joined: 10 Oct 2012
Posts: 591
Re: If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value  [#permalink]

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Bunuel wrote:

Tough and Tricky questions: Algebra.

If 3x – 2y – z = 32 + z and $$\sqrt{3x} - \sqrt{2y + 2z} = 4$$, what is the value of x + y + z?

(A) 3
(B) 9
(C) 10
(D) 12
(E) 14

Kudos for a correct solution.

From equation 1, we know that 3x-32 = 2y+2z.

Now, we also know that $$\sqrt{3x} - \sqrt{2y + 2z} = 4$$
or
$$\sqrt{3x} - 4 = \sqrt{2y + 2z}$$ -->$$\sqrt{3x} - 4 = \sqrt{3x-32}$$

Square on both sides, to get $$3x+16 -8\sqrt{3x} = 3x-32$$, cancel 3x on both sides, and we get

$$8\sqrt{3x} = 48 --> x = 12$$

Thus, 3x-32 = 2y+2z, hence, y+z = 2 and x+y+z = 14.

E.
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Re: If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value  [#permalink]

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3
$$\sqrt{3x} - \sqrt{2y + 2z} = 4$$

Say $$\sqrt{2y + 2z} = 2$$

then y = 1, z = 1

Say $$\sqrt{3x} = 6$$

then x = 12

These values also satisfy equation 3x – 2y – z = 32 + z

x+y+z = 12+1+1 = 14

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Re: If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value  [#permalink]

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3x – 2y – z = 32 + z means 3x – 2y – 2z = 32
Or 3x – (2y +2z) = 32

This is of the form $$a^2 - b^2 = 32$$, i.e., (a+b)*(a-b) = 32

The second equation is of the form $$a - b = 4$$. This means $$a + b = 32/4 = 8$$

Now a+b = 8, a-b=4. So 2a = 12, or a=6. (a is \sqrt{(3x)}). So x is 12.

Now, \sqrt{(3x)} - \sqrt{(2y + 2z)} = 4, or 6-\sqrt{(2y + 2z)} = 4
\sqrt{(2y + 2z)} = 2, or: (2y + 2z) = 4
(2y + 2z) + 2x = 4 + 2*12 = 28, or x+y+z = 14.
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GRE 1: Q169 V154 Re: If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value  [#permalink]

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PareshGmat wrote:
$$\sqrt{3x} - \sqrt{2y + 2z} = 4$$

Say $$\sqrt{2y + 2z} = 2$$

then y = 1, z = 1

Say $$\sqrt{3x} = 6$$

then x = 12

These values also satisfy equation 3x – 2y – z = 32 + z

x+y+z = 12+1+1 = 14

The values 1,1 would not always work ..
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Re: If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value  [#permalink]

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Hey! Great solutions. I got this after 2 tries. Anyone know a shortcut to this sum? Re: If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value   [#permalink] 19 Apr 2019, 19:42
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If 3x – 2y – z = 32 + z and √(3x) - √(2y + 2z) = 4, what is the value

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