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Re: If 4<(7x)/3, which of the following must be true?
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04 Sep 2015, 21:06
mn2010 wrote: If 4<(7x)/3, which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive A) II only B) III only C) I and II only D) II and III only E) I, II and III I am confused about statement II ???? Correct answer is only III. According to II, x can be 2 or 10. But according to the given question x<5. Hence II can not be true always.



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Re: If 4<(7x)/3, which of the following must be true?
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23 Sep 2015, 08:27
got this question correct, but selected wrong option as statement D is partially correct .



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Re: If 4<(7x)/3, which of the following must be true?
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02 Jan 2016, 14:15
Bunuel wrote: mn2010 wrote: If 4<[(7x)/3], which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
I am not confused about statement II ???? Good question, +1. Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D. Hope it's clear. Hi Bunuel, Statements I and III are perfectly clear. But let me ask you a question about statement II to clear all my doubts, if you don´t mind. Question stem states that x < 5 and then asks "if this is true, then what else must be true?" Statement II gives us 2 options. Case A: x > 1 OR Case B: x < 5. Since the question stem already stated that x < 5, then Case A cannot be true (since x cannot be less than 5 and bigger than 1 at the same time) and Case B must be true. Therefore, Statement II must be true. Is this reasoning correct? Thank you so much!



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Re: If 4<(7x)/3, which of the following must be true?
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03 Jan 2016, 10:16
minwoswoh wrote: Bunuel wrote: mn2010 wrote: If 4<[(7x)/3], which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
I am not confused about statement II ???? Good question, +1. Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D. Hope it's clear. Hi Bunuel, Statements I and III are perfectly clear. But let me ask you a question about statement II to clear all my doubts, if you don´t mind. Question stem states that x < 5 and then asks "if this is true, then what else must be true?" Statement II gives us 2 options. Case A: x > 1 OR Case B: x < 5. Since the question stem already stated that x < 5, then Case A cannot be true (since x cannot be less than 5 and bigger than 1 at the same time) and Case B must be true. Therefore, Statement II must be true. Is this reasoning correct? Thank you so much! Yes. Basically we are given that x<5 and then asked whether x+3>2 is true. We know that if x < 5, then x+3>2 must be true.
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Re: If 4<(7x)/3, which of the following must be true?
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20 Mar 2016, 13:54
try to plug in any number less than 5 and check because that's the condition given in question.
x < 5 means x can be 6,7,8 .... x+3>2 when x= 6 => 6+3>2 true when x=100 => 100+3>2 true



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Re: If 4<(7x)/3, which of the following must be true?
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01 Apr 2016, 01:17
Bunuel wrote: Bunuel wrote: mn2010 wrote: If 4<[(7x)/3], which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
I am not confused about statement II ???? Good question, +1. Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D. Hope it's clear. Yes. Basically we are given that x<5 and then asked whether x+3>2 is true. We know that if x < 5, then x+3>2 must be true. Chiragjordan wrote: mn2010 wrote: If 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
Hey Everyone I am facing majo issues with this one .. the second statement specifies X>1 or X<5 now x can be 100 too hence it will make the inequality insufficient... I am rooting for B only
Someone i the thread mentioned X<5 is given right... but what if X is 100 .. i have every statement in this thread and still believe the answer is B ..
Can anyone tell me where am i doing wrong
P.S => DON'T tell me X<5 IS GIVEN Bunuel, Sorry that bother you but, in my humble opinion, it seems that Chiragjordan is correct. II is not true. A simple check can prove it : From II we have that Case A: x > 1 OR Case B: x < 5 From Case A let's take x = 0 4<[(7x)/3] => 4<[(70)/3]  is not true => Case A => is not working Because problem's type is MUST BE not COULD BE => the answer is B ( only III MUST BE true ) . Bunuel, please, could you confirm ?



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Re: If 4<(7x)/3, which of the following must be true?
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11 Apr 2016, 23:31
mn2010 wrote: If 4<(7x)/3, which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive A) II only B) III only C) I and II only D) II and III only E) I, II and III I am confused about statement II ???? Simplify 4<(7x)/3 and you get x < 5. Any of the statement says it would be true. (I) 5 < X i.e. X > 5 NOT true. (II) x+3>2  range for this is 5 < X < 5. True. (III) (x+5) i.e. x5 as x is less than 5 the values it would take will be 6, 7 and so on. in all these cases (x+5) will be positive. True Hence D is the correct answer.
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Re: If 4<(7x)/3, which of the following must be true?
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01 Nov 2016, 20:11
Bunuel wrote: mn2010 wrote: If 4<[(7x)/3], which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
I am not confused about statement II ???? Good question, +1. Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D. Hope it's clear. In II. x+3>2 If we have two cases where x>1 and x<5, then how can it MUST BE TRUE? Not 100% clear on this. Thanks for Looking into this. Sandeep



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Re: If 4<(7x)/3, which of the following must be true?
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02 Jan 2017, 21:31
Bunuel wrote: mn2010 wrote: If 4<[(7x)/3], which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
I am not confused about statement II ???? Good question, +1. Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D. Hope it's clear. Regarding the option II shouldn't the condition x>1 be satisfied ?



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Re: If 4<(7x)/3, which of the following must be true?
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03 Jan 2017, 01:02
Animatzer wrote: Bunuel wrote: mn2010 wrote: If 4<[(7x)/3], which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
I am not confused about statement II ???? Good question, +1. Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D. Hope it's clear. Regarding the option II shouldn't the condition x>1 be satisfied ? Check here: if47x3whichofthefollowingmustbetrue99015.html#p853541
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Re: If 4<(7x)/3, which of the following must be true?
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23 Mar 2017, 07:02
let's simpify from the beginning: 12<7x x<5 let's test 1: doesn't work C,E out let's test 2: 6+3>2 works fine let's test 3: (6+5)= 1, hence, positive
Answer is D



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Re: If 4<(7x)/3, which of the following must be true?
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05 Apr 2017, 09:24
mn2010 wrote: If 4<(7x)/3, which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive A) II only B) III only C) I and II only D) II and III only E) I, II and III I am confused about statement II ???? Responding to a pm: Quote: In this question, I found that option two has two ranges. x >  or x < 5. So why this becomes sufficient? Don't we need only one clear answer to prove the sufficiency? If I have three ranges and one of them is good to prove the sufficiency, then also can we discard the other two?
You are given that x < 5. You obtain this because you are given that 4<(7x)/3. So x can take values such as 5.4, 6, 100, 54637 etc Which of the following MUST BE TRUE? II. x+3>2 Gives x < 5 OR x > 1 For every value that x can take, is this statement true? Yes. For every value that x can take it is "'less than 5" or "more than 1". All our values are actually "less than 5". We need x to satisfy either "x < 5" or "x > 1".
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Re: If 4<(7x)/3, which of the following must be true?
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29 May 2017, 21:50
mn2010 wrote: If 4<(7x)/3, which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive A) II only B) III only C) I and II only D) II and III only E) I, II and III I am confused about statement II ???? OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/if47x3w ... 68681.html OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/if47x3w ... 68681.html
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Re: If 4<(7x)/3, which of the following must be true?
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