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# If 5^2x+5/(5^3)(7y) = 28y^2, then 5(5^y - 1) =? 6 9 10 14 25

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Senior Manager
Joined: 11 May 2004
Posts: 453

Kudos [?]: 57 [0], given: 0

Location: New York
If 5^2x+5/(5^3)(7y) = 28y^2, then 5(5^y - 1) =? 6 9 10 14 25 [#permalink]

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08 Nov 2005, 20:51
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If 5^2x+5/(5^3)(7y) = 28y^2, then 5(5^y - 1) =?

6
9
10
14
25

If my diction is not clear the numerator is 5 and it is raised to the entire 2x+5.

Also, in the 'then' part, the 5 in the bracket is raised to y only.

Kudos [?]: 57 [0], given: 0

Current Student
Joined: 28 Dec 2004
Posts: 3345

Kudos [?]: 325 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

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08 Nov 2005, 22:48
too tired...will do it tommorow morning..

desiguy wrote:
If 5^2x+5/(5^3)(7y) = 28y^2, then 5(5^y - 1) =?

6
9
10
14
25

If my diction is not clear the numerator is 5 and it is raised to the entire 2x+5.

Also, in the 'then' part, the 5 in the bracket is raised to y only.

Kudos [?]: 325 [0], given: 2

Director
Joined: 21 Aug 2005
Posts: 785

Kudos [?]: 31 [0], given: 0

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08 Nov 2005, 22:50
fresinha12 wrote:
too tired...will do it tommorow morning..

I geuss it is already tomorrow morning for you

Kudos [?]: 31 [0], given: 0

Re: Exponents   [#permalink] 08 Nov 2005, 22:50
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# If 5^2x+5/(5^3)(7y) = 28y^2, then 5(5^y - 1) =? 6 9 10 14 25

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