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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
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GMATPrepNow wrote:
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13


52x=1400-604 = 796

13x = 199 --> (1)

151 + 13y = 350

13y = 350-151 =199

13y = 199 --> (2)

1 - 2 gives us 0

Hence C
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
1
Kudos
GMATPrepNow wrote:
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13


If we multiply the 2nd equation by 4, we will get 604 + 52y = 1400(similar to 52x + 604 = 1400).

Therefore, the value of x-y is 0(Option C)
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
1
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GMATPrepNow wrote:
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13


This can be solved in many ways. But the easiest of all - is to find relation between two equation.
This will take less time to solve this problem and will enable us to solve difficult question with more time in hand.

Let's take 2nd equation: 151 + 13y = 350. The only hint we have here is 13*4 = 52.
So lets multiply this equation by 4 ==> 604 + 52y = 1400.

The first equation is 52x + 604 = 1400.

==> x and y have same value. Hence x-y = 0.
Ans - C
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
1
Kudos
GMATPrepNow wrote:
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13


If we divide 52x + 604 = 1400 by 4, it becomes 13x + 151 = 350. It means x = y

So x - y = 0

C.
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
BrentGMATPrepNow wrote:
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13

\(52x = 796\)

Or, \(x = 15.\)xxxx

\(13y = 199\)

Or, \(y = 15.\)xxxx

Hence, \(x – y = 15 - 15 = 0\), Answer must be (C)
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0 --> correct: 52x + 604 = 1400 => 13x +151=350 =>13x=350-151 --(i) & 151 + 13y = 350 => 13y=350-151--(ii) => so (i)-(ii) =>13x-13y=0 => x-y=0
D) 11/52
E) 11/13
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
It’s simple
1400= 604+52(15.30) > How 15.30 > 1400-604=796 >796/52 > x=15.30
Same for
350 = 151+13(15.30) > 350-151 = 191/13=15.30 >y=15.30
X-Y =15.30-15.30 =0

Posted from my mobile device
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
Expert Reply
52x + 604 = 1400 and 151 + 13y = 350

=> Divide the equation by '4' we get => 13x + 151 = 350

=> 13x - 13 y = 0

=> x - y = 0

Answer C
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
Take Eqn 52x + 604 = 1400
Divide both sides by 4
=> 13x +151 = 350
=>13x=199------1

Take Eqn 151 + 13y = 350
=> 13y=350-151 = 199------2

Subtracting 1 & 2

=>13x-13y=0
=>x-y=0

Hence C
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Re: If 52x + 604 = 1400 and 151 + 13y [#permalink]
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