Engr2012 wrote:
kanigmat011 wrote:
If 53 students are enrolled in both the CS103 (Algorithms and Data Structures) and the M101 (Mathematics for Computer Science) classes, how many of the CS103 students are not enrolled in M101?
(1) 72 students are taking M101.
(2) 59 students are taking CS103
I believe you are getting confused with the extra bit of information regarding CS103 and M101. Refer to the attached 2X2 Matrix for this question.
You are given that CS103 students not taking M101 = 53
Attachment:
QUESTION.jpg
Per statement 1, total number of students taking M101 = 72. You can not calculate 'x'. Not sufficient.
Attachment:
S1.jpg
Per statement 2, total number of students taking CS103=59 and out of these, 53 take both the courses. Thus the ones taking CS103 only = 59-53 = 6. Hence sufficient.
B is thus the correct answer.
Hope this helps.
Attachment:
S2.jpg
Hi Engr2012,
Thanks for explaining this,
But no where its mentioned that its just two classes and what if there are more than 2 classes.
Aren't we missing the case of none of the two
Apart from 6 there can be few students who have not opted for either of the calls so they should also be part of answer.
Is there something I am missing?