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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
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Properties in action->
1->When we multiply a positive integer x with another positive integer n,the number of prime factors of nx may be equal to x or greater than x.
2->\(X\) and \(X^n\) always have the exact same prime factors.
Case 1
In this case since 5x^2 has 2 prime factors.
So x can have one prime factors => and that will not be 5 so that 5x^2 has two primes.
OR
Case 2
In this case x can have two prime factors including 5 => e.g => x=5*3 => 5x^2=> 2 prime factors.
Hence At the most -> x can have 2 prime factors.


Hence B.
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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
The tricky moment here is to notice that (5x)^2 has two different prime factors. The author does not mention the real number of prime factors. For example, the number 100 = 2*2*5*5, so has 4 prime factors, but it only has 2 distinct prime factors, 5 and 2.
So in this question, x can have the maximum of 2 prime factors, one can be something like 2,3,7 and the other 5 to maximize the possibilities of having prime factors.
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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
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suprememodelrus wrote:
If 5x^2 has two different prime factors, at most how many different prime factors does x have?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


Since 5x^2 has two different prime factors, and one of them is 5, then x can have only one prime other than 5. For instance, if x = 10, then 5x^2 = 5*100 = 500; which has two prime factors, namely 2 and 5. So x can have at most two prime factors, i.e., 5 and some other prime

Answer: B
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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
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X^2 is just a X multiplied by itself.
So it won't increase / decrease the number of prime factors.

for e.g 6 (6=2x3) has two prime factors
36 (36=2x2x3x3) also has two prime factors

Thus, # of prime factors always remains same for x, and x^2

Now coming to the question
5*X^2 has 2 prime factors
Thus 5*X will also have 2 prime factors
So, X can have at most 2 prime factors ( one of which'd be 5)
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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
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5\(x^2\) has two different prime factors.

=> 'x' can take any value of prime factor-like 2, 3, 7 so we have 1 prime factor for x.

=> 'x' can also have prime factor '5'.[5\(x^2\) still have 2 different prime factors].

Answer B
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If 5x^2 has two different prime factors, at most how many di [#permalink]
Hi,

5x^2 has two different prime factors,therefore x could be 5*3^2 and x can at most have 2 different prime factors.

Answer B)
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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
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Re: If 5x^2 has two different prime factors, at most how many di [#permalink]
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