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If 6 men can do a piece of work in 30 days of 9 hours each, [#permalink]

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15 Jan 2014, 22:50

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If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?

A. 61 B. 64 C. 84 D. 81 E. 94

Please help explains using rates formulae as I could not get the answer. Thanks

Re: If 6 men can do a piece of work in 30 days of 9 hours each, [#permalink]

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16 Jan 2014, 01:07

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smartyman wrote:

If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours? A. 61 B. 64 C. 84 D. 81 E. 94

Please help explains using rates formulae as I could not get the answer. Thanks

Amount of work done by 6 men working 30 days working 9 hrs each = 30 * 9 * 6 Let the number of people required for the 2nd case = X

Then X * 25 * 8 = 30 * 9 * 6 * 10 = > X = 81 - Option D)
_________________

If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?

A. 61 B. 64 C. 84 D. 81 E. 94

Please help explains using rates formulae as I could not get the answer. Thanks

Or you can do it using joint variation:

Number of men required = 6 * (30/25) * (9/8) * 10 = 81

Re: If 6 men can do a piece of work in 30 days of 9 hours each, [#permalink]

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18 Jul 2014, 03:21

Can someone please explain any other method, preferably the w=rt method. Work rate problems always seem so simple but I always go wrong or am stuck. I was not able to grasp it even after going through the two approaches. Thank you.

In this type of problems, converting for unit values will make it easy to solve.

Take a look at the first sentence. We can say, to do the work in 1 day of 9 hours each will take 6*30 men. To do the work in 25 days will take (6*30) /25 men Similarly adding the info, that to do the work in a day of 8 hours instead of 9 hours each will take (6 *30*9)/ (25*8) men To do 10 times the amount of work will take 10 * (6*30*9) / (25*8) = 81 men
_________________

If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?

A. 61 B. 64 C. 84 D. 81 E. 94

Please help explains using rates formulae as I could not get the answer. Thanks

i.e. \(\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}\)

i.e. \(\frac{[6 * (30*9)]}{W} = \frac{[M_2 * (25*8)]}{(10*W)}\)

i.e. \(M_2 = 81\)

Answer: option D
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Re: If 6 men can do a piece of work in 30 days of 9 hours each, [#permalink]

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25 Sep 2016, 12:06

If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?

A. 61 B. 64 C. 84 D. 81 E. 94

6*30*9=1620 total man hours to do work let m=number of men needed m*25*8*1/1620=10 m=81 men D.

If 6 men can do a piece of work in 30 days of 9 hours each, [#permalink]

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30 Nov 2017, 12:56

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smartyman wrote:

If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?

A. 61 B. 64 C. 84 D. 81 E. 94

Please help explains using rates formulae as I could not get the answer. Thanks

One version of the rate formula approach . . . Use standard W = RT formula, but add (# of workers or machines) to R*T, thus: W = #*R*T

Work = (# of workers) * individual rate * time

Scenario 1

Get individual rate from first scenario, where t = (30 * 9hrs = 270 hrs)

Work = # * r * t

1 = 6 * ?? * 270

1 = r * 1620

r = \(\frac{1}{1620}\)

Scenario 2

At that rate, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours? t = (25 * 8 hrs = 200 hrs)

Work = # * r * t

10 = ?? * \(\frac{1}{1620}\) * 200

10 = # * \(\frac{200}{1620}\)

# of workers = \(\frac{10}{(\frac{200}{1620})} =\)

# of workers =\((10 * \frac{1620}{200})=(\frac{1620}{20})=\frac{162}{2}= 81\)

Answer D
_________________

At the still point, there the dance is. -- T.S. Eliot Formerly genxer123

If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?

A. 61 B. 64 C. 84 D. 81 E. 94

The hourly rate of the 6 men is 1/(30 x 9) = 1/270. If we let x = the number of men needed to do 10 times the work when they work for 25 days of 8 hours, then the hourly rate of these x men must be 10/(25 x 8) = 10/200 = 1/20. We can create the following proportion and solve for x:

6/(1/270) = x/(1/20)

1620 = 20x

x = 1620/20 = 81

Answer: D
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