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If 6 men can do a piece of work in 30 days of 9 hours each,
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15 Jan 2014, 23:50
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If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours? A. 61 B. 64 C. 84 D. 81 E. 94 Please help explains using rates formulae as I could not get the answer. Thanks
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Re: If 6 men can do a piece of work in 30 days of 9 hours each,
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21 Jul 2015, 22:25
smartyman wrote: If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?
A. 61 B. 64 C. 84 D. 81 E. 94
Please help explains using rates formulae as I could not get the answer. Thanks CONCEPT: \(\frac{(Machine_Power * Time)}{Work} = Constant\)i.e. \(\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}\) i.e. \(\frac{[6 * (30*9)]}{W} = \frac{[M_2 * (25*8)]}{(10*W)}\) i.e. \(M_2 = 81\)Answer: option D
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Re: If 6 men can do a piece of work in 30 days of 9 hours each,
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16 Jan 2014, 02:07
smartyman wrote: If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours? A. 61 B. 64 C. 84 D. 81 E. 94
Please help explains using rates formulae as I could not get the answer. Thanks Amount of work done by 6 men working 30 days working 9 hrs each = 30 * 9 * 6 Let the number of people required for the 2nd case = X Then X * 25 * 8 = 30 * 9 * 6 * 10 = > X = 81  Option D)



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Re: If 6 men can do a piece of work in 30 days of 9 hours each,
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16 Jan 2014, 21:53
smartyman wrote: If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?
A. 61 B. 64 C. 84 D. 81 E. 94
Please help explains using rates formulae as I could not get the answer. Thanks Or you can do it using joint variation: Number of men required = 6 * (30/25) * (9/8) * 10 = 81 Check this link to see how to solve such questions: http://www.veritasprep.com/blog/2013/02 ... variation/
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Re: If 6 men can do a piece of work in 30 days of 9 hours each,
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18 Jul 2014, 04:21
Can someone please explain any other method, preferably the w=rt method. Work rate problems always seem so simple but I always go wrong or am stuck. I was not able to grasp it even after going through the two approaches. Thank you.



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If 6 men can do a piece of work in 30 days of 9 hours each,
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18 Jul 2014, 04:38
In this type of problems, converting for unit values will make it easy to solve. Take a look at the first sentence. We can say, to do the work in 1 day of 9 hours each will take 6*30 men. To do the work in 25 days will take (6*30) /25 men Similarly adding the info, that to do the work in a day of 8 hours instead of 9 hours each will take (6 *30*9)/ (25*8) men To do 10 times the amount of work will take 10 * (6*30*9) / (25*8) = 81 men
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Re: If 6 men can do a piece of work in 30 days of 9 hours each,
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25 Sep 2016, 13:06
If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?
A. 61 B. 64 C. 84 D. 81 E. 94
6*30*9=1620 total man hours to do work let m=number of men needed m*25*8*1/1620=10 m=81 men D.



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If 6 men can do a piece of work in 30 days of 9 hours each,
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30 Nov 2017, 13:56
smartyman wrote: If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?
A. 61 B. 64 C. 84 D. 81 E. 94
Please help explains using rates formulae as I could not get the answer. Thanks One version of the rate formula approach . . . Use standard W = RT formula, but add (# of workers or machines) to R*T, thus: W = #*R*T Work = (# of workers) * individual rate * timeScenario 1Get individual rate from first scenario, where t = (30 * 9hrs = 270 hrs) Work = # * r * t1 = 6 * ?? * 270 1 = r * 1620 r = \(\frac{1}{1620}\)Scenario 2At that rate, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours? t = (25 * 8 hrs = 200 hrs) Work = # * r * t 10 = ?? * \(\frac{1}{1620}\) * 200 10 = # * \(\frac{200}{1620}\)# of workers = \(\frac{10}{(\frac{200}{1620})} =\) # of workers = \((10 * \frac{1620}{200})=(\frac{1620}{20})=\frac{162}{2}= 81\)Answer D
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Re: If 6 men can do a piece of work in 30 days of 9 hours each,
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01 Dec 2017, 07:49
smartyman wrote: If 6 men can do a piece of work in 30 days of 9 hours each, how many men will it take to do 10 times the amount of work if they work for 25 days of 8 hours?
A. 61 B. 64 C. 84 D. 81 E. 94 The hourly rate of the 6 men is 1/(30 x 9) = 1/270. If we let x = the number of men needed to do 10 times the work when they work for 25 days of 8 hours, then the hourly rate of these x men must be 10/(25 x 8) = 10/200 = 1/20. We can create the following proportion and solve for x: 6/(1/270) = x/(1/20) 1620 = 20x x = 1620/20 = 81 Answer: D
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If 6 men can do a piece of work in 30 days of 9 hours each,
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29 Nov 2019, 06:35
The best way to tackle any of these problems is to follow this sequence (be it any question)
No. of workers  Time  work 6  30x9 hrs  1
we need to find:
?  25x8  10
so, by unitary method:
6  1  1/ (30x9)
1  1  1/ (30x9)*(6)
1  25x8  25x8/ (30x9)*(6)
so,
{(10)* (30x9)*(6)/ (25x8)}  25x8  10 =81




If 6 men can do a piece of work in 30 days of 9 hours each,
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29 Nov 2019, 06:35






