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If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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30 Jul 2018, 21:56
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If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293)
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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30 Jul 2018, 23:12
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4a}\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Bunuel, pl relook ..\(b = 1 + \frac{1}{4a}\) should be \(b = 1 + \frac{1}{4}*a\) otherwise you will not get the denominator as a multiple of 4 \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}=1+\frac{1}{2^2}+\frac{1}{2^4}+\frac{1}{2^6}\)... it is a geometric progression sum = \(\frac{a(1r^n)}{1r}=1*(1\frac{1}{4}^4)/(1\frac{1}{4})=\frac{255}{256}/\frac{3}{4}=\frac{255*4}{256*3}=\frac{85}{64}\)... \(b = 1 + \frac{a}{4}=1+\frac{85}{64*4}=\frac{341}{256}\).... \(ab=\frac{85}{64}\frac{341}{256}=\frac{340341}{256}=\frac{1}{256}\) B
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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31 Jul 2018, 02:47
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? a = 1 + 1/4 + 1/16 + 1/64 a = ( 64 + 16 + 4 + 1 ) / 64 a = 85 / 64 Now, b = 1 + 1/4 * 85/64 b = 1 + 85/256 b = 341/256 Therefore, a  b = 85/64  341/256 a  b = ( 85*4  341 ) / 256 a  b = (340  341)/256 a  b =  1 / 256 Hence, B.
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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10 Aug 2018, 19:06
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ?
A. 85/256
B. 1/256
C. 1/4
D. 125/256
E. 169/256 a  b a  (1 + ¼a) ¾a  1 ¾(1 + ¼ + 1/16 + 1/64)  1 ¾(64/64 + 16/64 + 4/64 + 1/64)  1 ¾(85/64)  1 255/256  256/256 1/256 Answer: B
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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12 Jan 2019, 07:24
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Hi, this is my first post. Hope I did it correctly. \(a=1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}\) \(b=1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}+\frac{1}{256}\) \(ab=1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}1\frac{1}{4}\frac{1}{16}\frac{1}{64}\frac{1}{256}\) or \(ab=11+\frac{1}{4}\frac{1}{4}+\frac{1}{16}\frac{1}{16}+\frac{1}{64}\frac{1}{64}\frac{1}{256}\) Just simplify: \(=\frac{1}{256}\)



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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30 Jul 2018, 22:49
Value of a = 1 + 1/4 = 1.25 (ignoring other bit which will make it slightly bigger than 1.25) Value of b = 1 + 1/(4*1.25) = 1 + 1/5 = 1.20
Roughly a  b = 1.25  1.20 = .05 => Actual value of a will be slightly more than 1.25 and therefore, value of b will be slightly less than what is present. This will mean this difference will slightly bigger but not drastically big.
I will go with smaller option of D.
This is not a proper way to solve this query as it can be solve using equations or GP series etc in a proper manner but that will be too time consuming in exam.



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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31 Jul 2018, 09:49
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Easier way to do rather than using Geo series formula is using substitution method. \(b=1+\frac{1}{4} a\) \(b=a+\frac{1}{256}\) so, \(ba = \frac{1}{256}\)



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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06 Aug 2018, 02:42
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) BunuelI think this question is already appeared in OG Quantitative review 2018. Kindly verify
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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25 Aug 2019, 08:39
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Simple solution to this problem if you apply logic: We know that \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\) We're solving for a  b Plug a in for b so you get the following: (\(1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\))  (\(1 + \frac{1}{4}[1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\)] Distrubute \(\frac{1}{4}\) (\(1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\))  (\(1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64} + \frac{1}{256}\)] The values in Red cross out, leaving you with \(\frac{1}{256}\) (\(1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\))  (\(1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) + \(\frac{1}{256}\)] Answer B



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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28 Oct 2019, 05:36
StudiosTom wrote: chetan2u wrote: Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4a}\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Bunuel, pl relook ..\(b = 1 + \frac{1}{4a}\) should be \(b = 1 + \frac{1}{4}*a\) otherwise you will not get the denominator as a multiple of 4 \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}=1+\frac{1}{2^2}+\frac{1}{2^4}+\frac{1}{2^6}\)... it is a geometric progression sum = \(\frac{a(1r^n)}{1r}=1*(1\frac{1}{4}^4)/(1\frac{1}{4})=\frac{255}{256}/\frac{3}{4}=\frac{255*4}{256*3}=\frac{85}{64}\)... \(b = 1 + \frac{a}{4}=1+\frac{85}{64*4}=\frac{341}{256}\).... \(ab=\frac{85}{64}\frac{341}{256}=\frac{340341}{256}=\frac{1}{256}\) B Hi chetan2u, Can you please elaborate the geometric progression formula aind its application. HI, A GP is a series where each successive number is SOME times the preceding term and this SOME could be any number. This is also referred as the RATIO or simply r. so if a, b, c,d ois the series in GP, b/a=r... If 2, 4, 6, 8..r=4/2=2 If 4, 2, 1, 1/2....r=2/4=1/2. There can be various applications which meets this requirement. Say a certain species doubles itself every year, or a certain amount of money increases by 10% every 4 months and so on.
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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30 Jul 2018, 23:15
chetan2u wrote: Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4a}\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Bunuel, pl relook ..\(b = 1 + \frac{1}{4a}\) should be \(b = 1 + \frac{1}{4}*a\) otherwise you will not get the denominator as a multiple of 4 \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}=1+\frac{1}{2^2}+\frac{1}{2^4}+\frac{1}{2^6}\)... it is a geometric progression sum = \(\frac{a(1r^n)}{1r}=1*(1\frac{1}{4}^4)/(1\frac{1}{4})=\frac{255}{256}/\frac{3}{4}=\frac{255*4}{256*3}=\frac{85}{64}\)... \(b = 1 + \frac{a}{4}=1+\frac{85}{64*4}=\frac{341}{256}\).... \(ab=\frac{85}{64}\frac{341}{256}=\frac{340341}{256}=\frac{1}{256}\) B _______________ Edited. Thank you.



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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31 Jul 2018, 10:06
can this be done in 2 minutes?



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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13 Aug 2018, 04:52
whatfielddoido wrote: can this be done in 2 minutes? Apparently yes "73% (01:44) correct"
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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14 Aug 2018, 01:32
How I solved it in 30s.
a= 1+0.25+(small numbers)=almost 1.3 b= 1+0,25*1.3=1+ slightly more than 0.3. a  b= (less than) 1.3  (more than) 1.3 = negative, but close to 0.
Answer options allow for B as best answer choice. B is correct.



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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26 Aug 2018, 20:16
Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293) Hi Bunuel, I took the LCM of b=1+1/4a Then b became 5/4a I got the answer as 85/256 Why can't we take the LCM and do it this way? And if we can then either way, we must get the same answer.. Please help...thanks



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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26 Aug 2018, 21:11
Hi Bunuel, I took the LCM of b=1+1/4a Then b became 5/4aI got the answer as 85/256 Why can't we take the LCM and do it this way? And if we can then either way, we must get the same answer.. Please help...thanks[/quote] Hi zanaik89, Refer the highlighted portion, It should be : \(b=1+\frac{1}{4}a\)(2) =\(\frac{4+a}{4}\) (Though we don't require this step) a=1+\(\frac{1}{4} + \frac{1}{16} + \frac{1}{64}\)=\(\frac{64+16+4+1}{64}\)=\(\frac{85}{64}\)(1) Hence \(ab=\frac{85}{64}(1+\frac{1}{4}*\frac{85}{64})=\frac{85}{64}1\frac{85}{4*64}=\frac{(4*85)(4*64)85}{4*64}\)=\(\frac{1}{256}\) Another Method:\(a=1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}\) So, \(\frac{1}{4}a=\frac{1}{4}+\frac{1}{16}+\frac{1}{64}+\frac{1}{256}\) (Dividing both sides by 4) So, \(b=1+\frac{1}{4}a=1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}+\frac{1}{256}\) Hence, \(ab=(1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64})(1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}+\frac{1}{256})\) Or, \(a−b=−\frac{1}{256}\)
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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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09 Dec 2018, 12:11
Hello to everyone! Is there any way to solve this task in 1 minute, please? Any tricks or magic?
The task is not complicated, but the problem takes more than 1.5 to be solved out.
Thanks.



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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09 Jan 2019, 11:10
get value of A and B then substitute, you will easily get the answer.



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If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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26 Apr 2019, 21:56
a=1+1/4+1/4^2 +1/4^3
B=1+1/4a , substitue vaule a in to b
b= 1+1/4(1+1/4+1/4^2 +1/4^3 ) = 1+1/4+1/4^2 +1/4^3 +1/4^4
ab= 1+1/4+1/4^2 +1/4^3  (1+1/4+1/4^2 +1/4^3 +1/4^4 )
=1/4^4 =1/256



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Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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04 Aug 2019, 19:19
Tried both geometric progression method and substitution, and substitution was faster for me. Geometric progression just had too much calculation with all the fractions; substitution reduced the calculations. Given: \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64} = \frac{85}{64}\) \(b = 1 + (\frac{1}{4})*a\) Substitution Method: a  b \(= \frac{85}{64}  (1 + (\frac{1}{4})*(\frac{85}{64}))\) \(= \frac{85}{64}  \frac{64}{64}  (\frac{1}{4})*(\frac{85}{64})\) \(= \frac{21}{64}  (\frac{1}{4})*(\frac{85}{64})\) \(= \frac{84}{256}  \frac{85}{256}\) \(= \frac{1}{256}\) Answer is B \(\frac{1}{256}\) Bunuel wrote: If \(a = 1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64}\) and \(b = 1 + \frac{1}{4}a\), then what is the value of a – b ? A. 85/256 B. 1/256 C. 1/4 D. 125/256 E. 169/256 NEW question from GMAT® Quantitative Review 2019 (PS14293)




Re: If a = 1 + 1/4 + 1/16 + 1/64 and b = 1 + 1/4a, then what is the value
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