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# If (a-1)(b-2) =0, which of the following must be true ?

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If (a-1)(b-2) =0, which of the following must be true ?  [#permalink]

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12 Aug 2004, 19:23
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If (a-1)(b-2) =0, which of the following must be true ?

I. a=1 and b=2
II. if a is not = 1, then b=2
III. if a=1, then b is not=2

A. I only
B. II only
C. III only
D. I and II
E. II and III

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12 Aug 2004, 19:37
If (a-1)(b-2) =0, which of the following must be true ?

I. a=1 and b=2
II. if a is not = 1, then b=2
III. if a=1, then b is not=2

For (a-1)(b-2) = 0, a =1 OR b=2

(I) is out because of the and
(III) is out because it says if a=1, then b must not be 2, which is wrong. b can still be 0.
(II) satisfiy the logic. If a is not 1, then the only way the equation can go to 0 is for b to be equals to 2.

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12 Aug 2004, 19:40
D.
I is got directly from the equation so no problem.
II If a = say 3 then we have (3-1)(b-2)=0 or 2b=4 or b=2. This is true for any value of A.

III is not ok...b can be 2 or any other value.

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12 Aug 2004, 19:59
venksune wrote:
D.
I is got directly from the equation so no problem.
II If a = say 3 then we have (3-1)(b-2)=0 or 2b=4 or b=2. This is true for any value of A.

III is not ok...b can be 2 or any other value.

Venksune, please notice the question asks what MUST BE true. I can be true. The ans here is B
_________________

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Director
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12 Aug 2004, 20:01
Sorry guys...read it as a=1 or b=2..silly mistakes again.

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13 Aug 2004, 06:11
I still don't understand.

Can someone explain in detail ? Thank you.

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17 Aug 2004, 14:22
Choice 1

If a = 1 AND b is any number (1, 2, 100), the equation in the question will still be satisfied. So, Choice 1 is wrong.

Choice 3

It says if a is 1 then b is not 2. If a is 1, b can certainly be 2 and this can be checked by plugging in. So, Choice 3 is wrong.

Choice 2.

It says if a is not 1 then b is 2. This is correct. If a is not 1, and b is not 2, then the equation in the question cannot be satisfied. So if a is not 1, then b HAS to be 2 (which is what Choice 2 says) and if b is not 2 then a HAS to be 1. So Choice 2 is correct and the answer is B.

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17 Aug 2004, 14:22
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