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If a and b are integers, and |a| > |b|, is a |b| < a

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 13 Mar 2016, 00:52
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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 03:09
Raths wrote:
is a - |b| < a - b
canceling a from both sides , the eqn becomes |b| > b
so basically the eqn is asking if b is -ve or not . Therefore , we will check for that

1 . a < 0 , does not talk about b
2. ab >= 0 implies a>=0 and b>=0
or a<=0 and b<=0

therefore not sufficient

combining both we get b<=0 which is also not sufficient since b=0 does not satisfy the
main question . I hope doing this way you feel faster.
Also I think that the condition |a| > |b| is irrelevant to the question.


Can anyone tell me if this is a correct method or not?

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 08:50
If a and b are integers, and |a| > |b|, is a - |b| < a – b?

(1) a < 0

(2) ab >= 0

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 09:16

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 09:26
Thanks Bunnel. Sorry, I missed this discussion. Should I delete my other post?

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 09:28

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 09 May 2016, 23:25
I personally am always prefer the algebraic method to solve rather than mumber plugin. I came up with this way to solve. Please comment if it is acceptable or not.
Attachments

IMG-20160510-WA0001.jpg
IMG-20160510-WA0001.jpg [ 115.68 KiB | Viewed 596 times ]

File comment: I have not solved for the second statement and also combining both the statements because they are the subset as computed for the statement 1.

So the answer ie E

IMG-20160510-WA0003.jpg
IMG-20160510-WA0003.jpg [ 139.11 KiB | Viewed 596 times ]

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 19 Jun 2017, 10:08
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If a and b are integers, and |a| > |b|, is a |b| < a   [#permalink] 19 Jun 2017, 10:08

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