Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

a B^A <0 => B is essentially negative and A is Odd number. For B=A = -1 and for B=-1 and A=3 the values are different. b A^B <0 => A is essentially negative and B is an Odd number. For similar values the equation gives different outcomes.

for a+b, A=B= -1 and for A= -3 and B= -1 the values are different.Hence IMO E.

Under such condition we have to always check for A=B values and A> or <B values.
_________________

Visit -- http://www.sustainable-sphere.com/ Promote Green Business,Sustainable Living and Green Earth !!

Re: If A and B are nonzero integers, is A^B an integer? (1) B^A [#permalink]

Show Tags

23 Dec 2014, 16:14

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: If A and B are nonzero integers, is A^B an integer? (1) B^A [#permalink]

Show Tags

26 Feb 2016, 00:46

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

attempted twice.. got it wrong both times.. I choose A both the times...

Whenever you are quoting a user, use "@"before the correct username. I believe you want to ask inputs from mikemcgarry from Magoosh.

As for this question, it hinges on the observation that \(A^B\) will be <0 when A < 0 for B=odd. Thus for \(A^B\) to be an integer ---> A =\(\pm\) 1 and B can be any odd integer (\(\neq\) 0). Analyse the given statements in light of this information.

Per statement 1, \(B^A\)< 0 ---> The only possible case is B < 0 and A= odd. If B = -1, A = any power, you get a yes to the question asked but if B = -3 and A = 1, you get -1/3 = no for the question asked. Not sufficient.

Per statement 2, \(A^B\) < 0 ---> The only possible case is A<0 and B = odd. Same logic as that for statement 1. Not sufficient.

Combining, you get that A = B = odd negative integer and as such you get a yes if A=B=-1 but you get a NO for A=-3 and B = -1.

Re: If A and B are nonzero integers, is A^B an integer? (1) B^A [#permalink]

Show Tags

13 Mar 2016, 22:46

Engr2012 wrote:

Chiragjordan wrote:

Hey MIKE Can you help with this one..

attempted twice.. got it wrong both times.. I choose A both the times...

Whenever you are quoting a user, use "@"before the correct username. I believe you want to ask inputs from mikemcgarry from Magoosh.

As for this question, it hinges on the observation that \(A^B\) will be <0 when A < 0 for whatever value of B. Thus for \(A^B\) to be an integer ---> A =\(\pm\) 1 and B can be any integer (\(\neq\) 0). Analyse the given statements in light of this information.

Per statement 1, \(B^A\)< 0 ---> The only possible case is B < 0 and A= odd. If B = -1, A = any power, you get a yes to the question asked but if B = -3 and A = 1, you get -1/3 = no for the question asked. Not sufficient.

Per statement 2, \(A^B\) < 0 ---> The only possible case is A<0 and B = odd. Same logic as that for statement 1. Not sufficient.

Combining, you get that A = B = odd negative integer and as such you get a yes if A=B=-1 but you get a NO for A=-3 and B = -1.

Hence E is thus the correct answer.

Hope this helps.

Thank you so much for the explanation here is what i think i made the mistake=> In the first case i neglected A being 1 or -1 So combining the two statements => A can be -1 B=-21=> integer and A= anything but -1 ,B=anything => non integer.. Is this understanding correct? regards Also whats the point of tagging the name when they only respond when they want else they DON'T.. Regards Stone Cold Steve Austin
_________________

If A and B are nonzero integers, is A^B an integer? (1) B^A [#permalink]

Show Tags

08 Apr 2016, 06:10

2

This post received KUDOS

If \(a\) and \(b\) are nonzero integers, is \(a^b\) an integer?

(1) \(b^a\) is negative

This can be true when \(b\) is negative integer(odd or even) and \(a\) is odd(negative or postive) If \(a=1\), then all cases of \(a^b\) is an integer If \(a=3\), None of the cases give an integer for \(a^b\)

Not sufficient

(2) \(a^b\) is negative

Negative can be an integer or decimal or real number as well.

for \(b=1\) & \(a=-3,-2\) we have some values of \(a^b\) as integer and some are not integer(decimal) values.

Thus insufficient.

Combining 1 and 2 we get both a and b as odd and negative integers Try the intended expression \(a^b\) with values (a,b) as (-1,-3) and (-3,-1). we get both integer and non integer values -3 and -0.333. Thus combining both the statements is also insufficient.

Ans E _________________

The only time you can lose is when you give up. Try hard and you will suceed. Thanks = Kudos. Kudos are appreciated

http://gmatclub.com/forum/rules-for-posting-in-verbal-gmat-forum-134642.html When you post a question Pls. Provide its source & TAG your questions Avoid posting from unreliable sources.

Re: If A and B are nonzero integers, is A^B an integer? (1) B^A [#permalink]

Show Tags

02 May 2017, 16:31

If a and b are nonzero integers, is \(a^{b}\) an integer?

(1) \(b^{a}\) is negative (2) \(a^{b}\) is negative

Please explain the most efficient way to attack this question.

The KEY here is to pick numbers. Let's go:

1) \(b^{a}\) is negative - We know from this equation that a=odd AND b=negative -- TEST VALUES: > \(-3^{3}\) = -27. INTEGER. > \(-3^{-3}\) = \(\frac{-1}{27}\). NOT AN INTEGER. * KEY: b is negative, but a is just "odd"...this means a can be positive or negative, and this differentiator makes or breaks the problem

ELIMINATE A&D

\(a^{b}\) is negative - We know from this equation that a=negative AND b=odd -- TEST VALUES: > \(-5^{3}\) = -125. INTEGER. > \(-5^{-3}\) = \(\frac{-1}{125}\). NOT AN INTEGER. * KEY: a is negative, but b is just "odd"...this means b can be positive or negative, and this differentiator makes or breaks the problem

ELIMINATE B

Between C&E - We know from BOTH equations that BOTH a&b need to be ODD AND NEGATIVE. -- TEST VALUES: > \(-3^{-3}\) = \(\frac{-1}{27}\). NOT AN INTEGER. > \(-1^{-3}\) = 1. INTEGER.

HENCE, CORRECT ANSWER = E

Kudos please if you find this helpful

gmatclubot

Re: If A and B are nonzero integers, is A^B an integer? (1) B^A
[#permalink]
02 May 2017, 16:31

There’s something in Pacific North West that you cannot find anywhere else. The atmosphere and scenic nature are next to none, with mountains on one side and ocean on...

This month I got selected by Stanford GSB to be included in “Best & Brightest, Class of 2017” by Poets & Quants. Besides feeling honored for being part of...

Joe Navarro is an ex FBI agent who was a founding member of the FBI’s Behavioural Analysis Program. He was a body language expert who he used his ability to successfully...