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If s and k are positive integers, what is the remainder when s is divi

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If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post Updated on: 25 Oct 2018, 11:56
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If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

Originally posted by Jazzmin on 25 Oct 2018, 11:41.
Last edited by Jazzmin on 25 Oct 2018, 11:56, edited 1 time in total.
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If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post Updated on: 25 Oct 2018, 12:09
2
(A)

If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

1) 6!= 1*2*3*4*5*6*k = s => s is divisible by 5, remainder = 0
SUFFICIENT

2) s>5! => s> 1*2*3*4*5

s= 6! => remainder = 0
s = 6!+1 => remainder ≠ 0
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12.08.2018 MGMAT 680 (Q49, V33)

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Originally posted by Kaczet on 25 Oct 2018, 11:50.
Last edited by Kaczet on 25 Oct 2018, 12:09, edited 1 time in total.
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Re: If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post 25 Oct 2018, 11:51
Jazzmin wrote:
If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!



I/We am/are really interested to know how statement 2 is sufficient .

To me ..... 121, 1212, 123, 124, 125 ....... for that matter any positive integer GT 120 , could be s.

The query could be shaped towards the provided OA.... if we modify the 2nd statement as 2. s!>5!

Please advise.
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Please let me know if I am going in wrong direction.
Thanks in appreciation.

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Re: If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post 25 Oct 2018, 11:56
Kaczet wrote:
How is it D?

If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

1) 6!= 1*2*3*4*5*6*k = s => s is divisible by 5, remainder = 0
SUFFICIENT

2) s>5! => s> 1*2*3*4*5

s= 6! => remainder = 0
s = 6!+1 => remainder ≠ 0



Extremely sorry, posting more questions this one was the answer of other one.
OA is A. Changing in OP
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If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post 25 Oct 2018, 12:09
Jazzmin wrote:
Kaczet wrote:
How is it D?

If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

1) 6!= 1*2*3*4*5*6*k = s => s is divisible by 5, remainder = 0
SUFFICIENT

2) s>5! => s> 1*2*3*4*5

s= 6! => remainder = 0
s = 6!+1 => remainder ≠ 0



Extremely sorry, posting more questions this one was the answer of other one.
OA is A. Changing in OP


Thank you for clarifying. No problem :)
Cheers.
_________________

Going to take the real test in November...

21.07.2018 OG gmat prep 400 (Q26,V20)
28.07.2018 OG gmat prep 550 (Q42,V23)
04.08.2018 MGMAT 680 (Q50,V31)
12.08.2018 MGMAT 680 (Q49, V33)

OG GMAT Exam 3 & 4
01.11.2018 Exam 3 GMAT 710 (Q50, V35)
03.11.2018 Exam 4 GMAT 710 (Q50, V35)

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If s and k are positive integers, what is the remainder when s is divi &nbs [#permalink] 25 Oct 2018, 12:09
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