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If s and k are positive integers, what is the remainder when s is divi

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If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post Updated on: 25 Oct 2018, 12:56
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If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

Originally posted by Jazzmin on 25 Oct 2018, 12:41.
Last edited by Jazzmin on 25 Oct 2018, 12:56, edited 1 time in total.
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If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post Updated on: 25 Oct 2018, 13:09
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(A)

If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

1) 6!= 1*2*3*4*5*6*k = s => s is divisible by 5, remainder = 0
SUFFICIENT

2) s>5! => s> 1*2*3*4*5

s= 6! => remainder = 0
s = 6!+1 => remainder ≠ 0

Originally posted by Kaczet on 25 Oct 2018, 12:50.
Last edited by Kaczet on 25 Oct 2018, 13:09, edited 1 time in total.
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Re: If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post 25 Oct 2018, 12:51
Jazzmin wrote:
If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!



I/We am/are really interested to know how statement 2 is sufficient .

To me ..... 121, 1212, 123, 124, 125 ....... for that matter any positive integer GT 120 , could be s.

The query could be shaped towards the provided OA.... if we modify the 2nd statement as 2. s!>5!

Please advise.
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Please let me know if I am going in wrong direction.
Thanks in appreciation.
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Re: If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post 25 Oct 2018, 12:56
Kaczet wrote:
How is it D?

If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

1) 6!= 1*2*3*4*5*6*k = s => s is divisible by 5, remainder = 0
SUFFICIENT

2) s>5! => s> 1*2*3*4*5

s= 6! => remainder = 0
s = 6!+1 => remainder ≠ 0



Extremely sorry, posting more questions this one was the answer of other one.
OA is A. Changing in OP
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If s and k are positive integers, what is the remainder when s is divi  [#permalink]

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New post 25 Oct 2018, 13:09
Jazzmin wrote:
Kaczet wrote:
How is it D?

If s and k are positive integers, what is the remainder when s is divided by 5?
1. 6!*k=s
2. s>5!

1) 6!= 1*2*3*4*5*6*k = s => s is divisible by 5, remainder = 0
SUFFICIENT

2) s>5! => s> 1*2*3*4*5

s= 6! => remainder = 0
s = 6!+1 => remainder ≠ 0



Extremely sorry, posting more questions this one was the answer of other one.
OA is A. Changing in OP


Thank you for clarifying. No problem :)
Cheers.
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If s and k are positive integers, what is the remainder when s is divi   [#permalink] 25 Oct 2018, 13:09
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If s and k are positive integers, what is the remainder when s is divi

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