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If a and b are two different integers (positive or negative)

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Senior Manager
Joined: 20 Feb 2007
Posts: 256

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If a and b are two different integers (positive or negative) [#permalink]

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16 Mar 2007, 19:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If a and b are two different integers (positive or negative) and a is not equal to -b, is |a-b| > 1 or |b-a| > 1 always?

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Director
Joined: 13 Dec 2006
Posts: 506

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Location: Indonesia

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16 Mar 2007, 23:13
no its not always true

explanation.

Assume that both a and b are positive and a= b (though a is not equal to -b but can be equal to b) so !a-b! = 0, which is less than 1. also for the value of a = 2 and b = 3 the eq is not great than 1.

hence its not always true

regards,

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Senior Manager
Joined: 20 Feb 2007
Posts: 256

Kudos [?]: 62 [0], given: 0

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17 Mar 2007, 01:02

If a and b are two different integers (positive or negative) and a is not equal to b or -b, is |a-b| > 1 or |b-a| > 1 always?

Kudos [?]: 62 [0], given: 0

Director
Joined: 13 Dec 2006
Posts: 506

Kudos [?]: 243 [0], given: 0

Location: Indonesia

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17 Mar 2007, 01:18
Hi,

In that case also it wont be always true read my answer which says if a=2 and b=3 then !a-b! or !b-a! will be = 1 and not greater than 1.

regards,

Amardeep

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SVP
Joined: 01 May 2006
Posts: 1794

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17 Mar 2007, 02:02
Just one more thing

|a-b| = |(-1)*(b-a)| = |-1| * |b-a| = 1 * |b-a| = |b-a|

So, to consider |a-b| > 1, we consider |b-a| > 1

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Senior Manager
Joined: 20 Feb 2007
Posts: 256

Kudos [?]: 62 [0], given: 0

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17 Mar 2007, 02:38
Thanks Amardeep and Fig!

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17 Mar 2007, 02:38
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