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If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:

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If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:  [#permalink]

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New post Updated on: 08 Aug 2019, 16:02
2
1
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

80% (02:30) correct 20% (02:43) wrong based on 44 sessions

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If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:

A) 11
B) 12
C) 15
D) 28
E) 48

+1 kudo only if you like the question

Originally posted by chondro48 on 07 Aug 2019, 11:45.
Last edited by chondro48 on 08 Aug 2019, 16:02, edited 2 times in total.
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Re: If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:  [#permalink]

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New post 07 Aug 2019, 12:03
1
1
AB + CD + AC + BD
=> B(A+D) + C(A+D)
= (B+C)(A+D)

From the given equaation:
A + B -(B + C)+C + D = 5 - 4 + 6

A+D=7

therefore

(B+C)(A+D)
=4*7
=28
Ans D
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Re: If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:  [#permalink]

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New post 07 Aug 2019, 23:07
1
No constraints on \(A\), \(B\), \(C\) or \(D\).

So, let \(A=5\), \(B=0\), \(C=4\) and \(D=2\).
\(\implies AB+CD+AC+BD = 28\)

Answer is D.
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Re: If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:   [#permalink] 07 Aug 2019, 23:07
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If A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD is:

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